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Oxana [17]
3 years ago
9

NEED HELP 40 points !!!

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0

Answer:

11 is 4:6

12 is 0

Step-by-step explanation:

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How can graphing an inequality help to solve it
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It helps you see the equation in "picture" form.

Step-by-step explanation:

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4 years ago
you are helping to organize a soccer tournament by registering the participating teams. each week 666 teams register to particip
algol13

The graph that best represent the relationship between time and cost is option A as it is a proportional graph

<h3>How to know the graph that represent the relationship between time and number of team?</h3>

Each week 6 teams register to participate.

Therefore, for every week 6 team register to participate in the competition.

This simply implies as time increases , the number of participant in the competition also increase.

Therefore, the equation that can be use to represent this situation is as follows:

y = 6x

where

  • y = number of team registered
  • x = time in weeks.

Hence,  the graph that best represent the relationship between time and cost is option A as it is a proportional graph. The registered team increases as the time in weeks increase.

learn more on graph relationship here: brainly.com/question/12812258

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8 0
2 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
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