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valina [46]
2 years ago
15

Which ion is formed when an atom of fluorine (f) gains one electron? f–1 f–2 f 1 f 2

Chemistry
1 answer:
gregori [183]2 years ago
6 0

Answer:

If a fluorine atom gains an electron, it becomes a fluoride ion with an electric charge of -1.

Explanation:

hope this helps

pls mark brainliest

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The average height of the sunflower sprouts at the end of week 3 is  12.0

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3 years ago
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A pool owner adds a compound containing chlorine to the pool to disinfect it. However, too much of the compound is added. As a r
MrMuchimi

Answer: He could add a base to the pool to neutralize the acid.

Explanation:

Chlorine is used to disinfect the pools as it produces hypochlorous acid in water. This hypochlorous acid is unstable and gives hydrochloric acid and nascent oxygen which is used to disinfect.

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The excess acid is neutralized by adding base which produces salt and water and thus decrease the acidity.

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Adding more acid would increase the acidity further.

3 0
3 years ago
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What is the name of the scientist who discovered that atoms have positive charges
sukhopar [10]
Atoms have positive charges? or nuclei? Rutherford conducted the infamous gold foil experiment from which he concluded an atom mist contain a dense positively charged part with a orbiting shell of negative parts. That model was refined many times to form the current model of the atom.
5 0
4 years ago
What is the concentration of FeCl3 in a solution prepared by dissolving 10.0 g of FeCl3 in enough water to make 275 mL of soluti
puteri [66]

Answer: The concentartion of solution will be 0.224 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute =\frac{\text{Given mass}}{\text{Molar mass}}=\frac{10.0g}{162.2g/mol}=0.0616moles

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Now put all the given values in the formula of molarity, we get

Molarity=\frac{0.0616\times 1000}{275ml}=0.224mole/L

Therefore, the concentration of solution will be 0.224 M

7 0
4 years ago
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