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kodGreya [7K]
3 years ago
6

When a fuel burns, what determines whether co or co^2 will be produced?

Chemistry
1 answer:
Galina-37 [17]3 years ago
5 0
If it is incomplete or complete combustion. Normally the problems question with tell you.

EX:
"In the presence of plenty of oxygen" is complete combustion
"Not enough oxygen present" is incomplete combustion
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What would be the final temperature of a 73.174g sample
madreJ [45]

The final temperature is -138 °C.

Explanation:

Using the equation of specific heat

Q = m*c* del T

We can easily find the final temperature of a 73.174 g of copper sample. As we know that specific heat is the amount of energy required to raise the temperature of the object to 1°C.

The specific heat of copper is known as 0.387 J/g°C and the initial temperature is said as 102 °C . The mass is given as 73.174 g. The heat released is 6800 J.

Since the heat is released the Q value will be negative.

-6800=0.387*73.174*(T_{final}-102)

T_{final}-102=\frac{-6800}{0.387*73.174} =-240

T_{final} = -240+102=-138

Thus, the final temperature is -138 °C.

3 0
3 years ago
Compare the vapor pressure curves of 1-butene and 1-heptene. Explain your reasoning.
bixtya [17]
Because for there health

5 0
3 years ago
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20 ML of a gas at 200 K is heated until the new volume is 55ML what is the final temperature of the gas
MrRa [10]

Answer:

T2 = 550K

Explanation:

From Charles law;

V1/T1 = V2/T2

Where;

V1 is initial volume

V2 is final volume

T1 is initial temperature

T2 is final temperature

We are given;

V1 = 20 mL

V2 = 55 mL

T1 = 200 K

Thus from V1/T1 = V2/T2, making T2 the subject;

T2 = (V2 × T1)/V1

T2 = (55 × 200)/20

T2 = 550K

8 0
3 years ago
In Chromium-53, the "53" represents the
alina1380 [7]

Answer:

The differemt isotopes that differ in atomic mass

Explanation:

4 0
3 years ago
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What is the limiting reactant if 12 moles of p4 react with 15 moles of o2?.
brilliants [131]

Answer:

see explanation

Explanation:

To determine limiting reactant divide mole quantities of reactants by the respective coefficient in the balanced equation. The smaller value is the limiting reactant.

    P₄      +     5O₂       => 2P₂O₅

12/1 = 12      15/5 = 3

O₂ is the limiting reactant. P₄ will be in excess when rxn stops.

4 0
2 years ago
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