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kodGreya [7K]
4 years ago
6

When a fuel burns, what determines whether co or co^2 will be produced?

Chemistry
1 answer:
Galina-37 [17]4 years ago
5 0
If it is incomplete or complete combustion. Normally the problems question with tell you.

EX:
"In the presence of plenty of oxygen" is complete combustion
"Not enough oxygen present" is incomplete combustion
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How many atoms are in 10 moles of chlorine?
enyata [817]

Answer:

I Found the answer is A

Explanation:

I use a calculator

3 0
3 years ago
What is the pOH of a<br> 2.6 x 10-6 M H+ solution?
melomori [17]

Answer:

Approximately 8.41 (assuming that the solution is at \rm 25^\circ C, under which K_{\rm w} = 10^{-14}.)

Explanation:

Let {\rm [H^{+}]} and {\rm [OH^{-}]} denote the concentration of \rm H^{+} and \rm OH^{-} respectively.

Let K_{\rm w} denote the self-ionization constant of water. The exact value of K_{\rm w}\! depends on the temperature of the solution. K_{\rm w} =10^{-14} at \rm 25^\circ C.

The product of {\rm [H^{+}]} and {\rm [OH^{-}]} in a solution (with \rm M, or moles per liter, as the unit) is supposed to be equal to the K_{\rm w} value of that solution at the corresponding temperature. In other words:

{\rm [H^{+}]} \cdot {\rm [OH^{-}]} = K_{\rm w}.

Rearrange to obtain an expression for {[\rm OH^{-}]}:

\begin{aligned}{\rm [OH^{-}]} &= \frac{K_{\rm w}}{[\rm H^{+}]}\end{aligned}.

Assume that the solution in this question is at \rm 25^\circ C (for which K_{\rm w} =10^{-14}.) For this solution:

\begin{aligned}{\rm [OH^{-}]} &= \frac{K_{\rm w}}{[\rm H^{+}]} \\ &= \frac{10^{-14}}{2.6 \times 10^{-6}}\approx 3.85\times 10^{-9}\; \rm M\end{aligned}.

Hence, the \rm pOH of this solution would be:

\begin{aligned}\rm pOH &= -\log_{10}{\rm [OH^{-}]} \\&\approx -\log_{10} (3.85 \times 10^{-9}) \approx 8.41 \end{aligned}.

3 0
3 years ago
Ammonium perchlorate NH4ClO4 is a powerful solid rocket fuel, used in the Space Shuttle boosters. It decomposes into nitrogen N2
Bas_tet [7]

Answer:

1.3 mol H₂O

Explanation:

Let's consider the decomposition reaction of ammonium perchlorate.

NH₄ClO₄(s) → 1/2 N₂(g) + 1/2 Cl₂(g) + O₂(g) + 2 H₂O(g)

As we can see in the balanced equation, the molar ratio of ammonium perchlorate to water is 1:2. The moles of water produced by the reaction of 2.5 mol of ammonium perchlorate.

2.5 mol NH₄ClO₄ × (2 mol H₂O / 1 mol NH₄ClO₄) = 1.3 mol H₂O

3 0
3 years ago
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A change in the force of gravity on an object will affect its what
Gnoma [55]

A change in the force of gravity on an object will affect its weight.

4 0
3 years ago
Determine the mass of hydrogen gas collected in a container if the gas occupies<br> 44.8 L at STP.
aleksandrvk [35]

Answer:

Hope this helps kinda got confused mid way

Explanation:

So the hydrogen sulphide is H2S for the molecular formula. Then the mass of hydrogen sulphide would be 1×2+32= 34g/mol At STP.

6 0
3 years ago
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