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4 years ago

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Solid Iron (III) reacts with oxygen gas to form iron (III) oxide, which is the compound we see when rust is present. Based on th

is information, which of the following is true?4Fe + 3O2---> 2Fe2O3A.4 moles of iron will need 2 moles of oxygen gas to fully reactB.12 moles of iron, if reacted completely, can produce 8 moles of iron (III) oxide.C.9 moles of oxygen can produce 9 moles of Iron (III) oxide
D.6 moles of oxygen can react completely to produce 6 moles of iron (III) oxide.E.none of the above

1 answer:

Sunny_sXe [5.5K]4 years ago

6 0

Answer:

Option E is correct. none of the above is correct

Explanation:

Step 1: Data given

Solid Iron (III) = Fe^3+

iron (III) oxide = Fe2O3

Molar mass Fe = 55.845 g/mol

Molar mass Fe2O3 = 159.69 g/mol

Step 2: The balanced equation:

4Fe + 3O2 → 2Fe2O3

4 moles of iron will need 2 moles of oxygen gas to fully react

⇒ This is false 4 moles of iron will need 3 moles of oxygen gas to fully react

B.12 moles of iron, if reacted completely, can produce 8 moles of iron (III) oxide.

⇒ This is false: When 12 moles of iron completely react, we can produce 12/2 = 6 moles of Fe2O3

C.9 moles of oxygen can produce 9 moles of Iron (III) oxide

⇒ This is false; 9 moles of O2 can produce 6 moles of Fe2O3

D.6 moles of oxygen can react completely to produce 6 moles of iron (III) oxide.

⇒ This is false 6 moles of O2 will react completely to produce 4 moles of Fe2O3

E.none of the above

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