The answer is b ...........................................................b............b..............
Answer:
0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
Step-by-step explanation:
Given the data in the question;
sample size n = 28
slope of the least squares regression line of y on x or sample estimate = 0.0623
standard error = 0.0224
95% confidence interval
level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05
degree of freedom df = n - 2 = 28 - 2 = 26
∴ the equation will be;
⇒ sample estimate ± ( t-test) ( standard error )
⇒ sample estimate ± (
) ( standard error )
⇒ sample estimate ± (
) ( standard error )
⇒ sample estimate ± (
) ( standard error )
{ from t table; (
) = 2.055529 = 2.056
so we substitute
⇒ 0.0623 ± ( 2.056 )( 0.0224 )
Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
2=8x-2/9
add 2/9 to both sides
2 and 2/9=8x
2=18/9
2 and 2/9=18/9+2/9=20/9
20/9=8x
multiply both sides by 9
20=72x
divide boht isdes by 72
20/72=x=5/18
The cost of 0.5 kg of bananas is 393.60 Colones as per the given conversion rates
Conversion rate of 1 USD to Costa Rican Colones = 518 Colones
The conversion rate of kg to pounds given in the question: 1 kg = 2.2025 lbs
Cost of one pound of bananas = $0.69
Bananas required to be purchased = 0.5kg
Converting 0.5kg bananas to pounds = 0.5*2.2025 = 1.10125 pounds
Cost of 1.10125 pound of bananas in dollars = 1.10125*0.69 = 0.7598
Cost of 1.1025 pounds of bananas in Colones = 0.7598*518 = 393.60 Colones
Hence, the cost is 393.60
Therefore, the cost of 0.5 kg bananas in Colones is 393.60 Colones
Learn more about conversion rate:
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