Let the second car meets the first car after n hours.
Second car starts with 8km/h, After succeeding hours his speed increases by 0.5 km.
So, Distance travelled by second car = 8 + 8.5 + 9
..... 8+(n-1) 0.5.....(1)
eqn. (1) sum of n terms Of A.P with first term 8
and common difference 0.5.
Sum of all the terms in equation 1 is also equals to the distance travelled by the first car for n hours, i.e. 10n km .
Now, we have (n/2) {16+(n-1) 0.5} = 10n........(2)
From equation (2) we get, n= 9
Hence, Both the cars will meet after 9 hours.
Hope it helps!
Answer:
107.14 ml of 70% dextrose and 392.86 ml of sterile water should be used.
Step-by-step explanation:
Since a label prints in the pediatric pharmacy satellite for 500 mL of dextrose 15% solution, but this concentration is not available commercially and needs to be compounded, and available in your pharmacy, you have a 1 L bag of sterile water and a 1 L bag of dextrose 70% available to compound the solution, to determine how many mLs of each are needed to make the requested solution, the following calculation must be performed:
500 x 0.15 = 75
100 x 0.70 = 70
A x 0.70 = 75
A = 75 / 0.70
A = 107.14
Therefore, 107.14 ml of 70% dextrose and 392.86 ml of sterile water should be used.
Answer:
.50
.25
3.33
.14
Step-by-step explanation:
hope this helps
Answer:
14
Step-by-step explanation:
72 rounds to 70
and 70 divided by 5 is 14
-2(2x+9)>-4x+9
1)We solve this inequation:
-2(2x+9)>-4x+9
-4x-18>-4x+9
-4x+4x-18>9
-18>9 This is not true, because -18<9; Therefore this inequation is never true.
Answer: this inequation is never true.
