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exis [7]
2 years ago
8

Hello PLS HELP.................

Mathematics
1 answer:
Norma-Jean [14]2 years ago
6 0
Answer: 11.5m^3
Explanation:
The volume of a rectangular prism (R):
length x width x height
Replacing with the values given and solving for v(Volume)
V(R) = 4x 2 x 1
V(R) = 8m3
Volume of a triangular prism (T): base area X
height
Base area = 1/2 x base × height (of the triangular base)
A = 1/2 x1x 3.5 = 1.75m2
Back with the volume formula:
V (T)= Ax h= 1.75 x 2 = 3.5m3
Adding both volumes:
8 +3.5 = 11.5 m3
Hope this explains it
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Using the z-distribution, it is found that since the p-value is less than 0.05, there is evidence that the mean amount of cereal in each box is different from 16 ounces at 0.05 significance.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the mean is not different to 16 ounces, that is:

H_0: \mu = 16

At the alternative hypothesis, it is tested if the mean is different, hence:

H_1: \mu \neq 16

<h3>What is the test statistic?</h3>

The test statistic is:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

In which:

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  • \mu is the value tested at the null hypothesis.
  • \sigma is the standard deviation of the population.
  • n is the sample size.

The parameters for this problem are:

\overline{x} = 15.75, \mu = 16, \sigma = 1.46, n = 150.

Hence:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{15.75 - 16}{\frac{1.46}{\sqrt{150}}}

z = -2.1

<h3>What is the p-value and the conclusion?</h3>

Using a z-distribution calculator, for a two-tailed test, as we are testing if the mean is different of a value, with z = -2.1, the p-value is of 0.0357.

Since the p-value is less than 0.05, there is evidence that the mean amount of cereal in each box is different from 16 ounces at 0.05 significance.

More can be learned about the z-distribution at brainly.com/question/16313918

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What’s the answer to this
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