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dmitriy555 [2]
3 years ago
9

The product of 0.1400 × 6.02 × 1023 will have how many significant figures?

Mathematics
2 answers:
vekshin13 years ago
6 0
3 significant figures.

0.1400 has 4 sig figs, 6.02 has 3, and 1023 has 4. when calculating significant figures for a multiplication or division equation, the product or quotient will have the same amount of significant figures as the number with the least amount of significant figures (in this case: 6.02).
MrMuchimi3 years ago
4 0

Answer:

3

Step-by-step explanation:

We are given that an expression

0.1400\times 6.02\times 10^{23}

We have to find the number of significant figures in the  product .

In 0.1400 , there are 4 significant figures

In 6.02\times 10^{23}, there are three significant figures

0.1400\times 6.02\times 10^{23}

0.8428\times 10^{23}

In multiplication, we have to precise the final answer to least significant figures.

Therefore, the final answer=0.843\times 10^{23}

Hence, three significant figures in the product.

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What is the slope line perpendicular to the equation 4x+3y=9
aleksandrvk [35]

Answer:

m=3/4

Step-by-step explanation:

first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)

we have the equation 4x+3y=9

subtract 4x from both sides

3y=-4x+9

divide by 3

y=-4/3x+3

perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1

so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1

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multiply by -3/4

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therefore the slope of the perpendicular line is 3/4

hope this helps!! :)

7 0
3 years ago
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anyanavicka [17]
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3 years ago
In the figure, Δ ABC Δ XYZ. What is the perimeter of ΔABC? Show your work.
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Answer:

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