Answer:
3
Step-by-step explanation:
We are given that an expression
![0.1400\times 6.02\times 10^{23}](https://tex.z-dn.net/?f=0.1400%5Ctimes%206.02%5Ctimes%2010%5E%7B23%7D)
We have to find the number of significant figures in the product .
In 0.1400 , there are 4 significant figures
In
, there are three significant figures
![0.1400\times 6.02\times 10^{23}](https://tex.z-dn.net/?f=0.1400%5Ctimes%206.02%5Ctimes%2010%5E%7B23%7D)
![0.8428\times 10^{23}](https://tex.z-dn.net/?f=0.8428%5Ctimes%2010%5E%7B23%7D)
In multiplication, we have to precise the final answer to least significant figures.
Therefore, the final answer=![0.843\times 10^{23}](https://tex.z-dn.net/?f=0.843%5Ctimes%2010%5E%7B23%7D)
Hence, three significant figures in the product.