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nadya68 [22]
3 years ago
7

Need help with A and C please :)

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0

First step: name the sides according to geometry standards, namely, the sides are named the same lowercase letter as the opposing angle. A revised diagram is shown.

Second step: we need to know the relationships of the trigonometric functions.

cosine(A)=cos(63) = adjacent / hypotenuse = AC/AB .................(1)

sine(A)=sin(63) = opposite / hypotenuse = CB/AB .......................(2)

We're given AB=7, so

using (1)

AC/AB=cos(63)

AC=ABcos(63)=7 cos(63) = 7*0.45399 = 3.17993 = 3.180 (to three dec. figures)

Using (2)

BC/AB=sin(63)

BC=ABsin(63) = 7 sin(63) = 7*0.89101 = 6.237 (to three dec. figures).


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Anyways have a good day/night :) I might be wrong, but I hope I helped at least a little

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