Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
+6=perimeter
Hope that helps :)
we know that
surface area of the cylinder=2*{area of the base}+perimeter of base*height
area of the base=pi*r²
r=40 ft
Area of base=pi*40²
Area of the base=1600*pi ft²
Perimeter of the base=2*pi*r
Perimeter of the base=2*pi*40
Perimeter of the base=80*pi ft
surface area of the cylinder=2*1600*pi+80*pi*17
surface area=4560*pi ft²
therefore
the answer is the option
4560π ft2
12 times 34 is 408. Hope that helped.
Answer:
- 6°F
Step-by-step explanation:
Given :
Temperature at 6:00 = 15°F
Temperature dropped by 9°F by 8:00
Temperature by 8:00 = 15°F - 9°F = 6°F
Temperature dropped another 12°F by 11:00
Hence, Temperature at 11:00 will be :
6°F - 12°F = - 6°F
Temperature at 11:00 = - 6°F
