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3241004551 [841]
3 years ago
8

Find the area of a sector with a central angle of 170° and a radius of 17 millimeters. Round to the nearest tenth. Question 9 op

tions: 857.5 mm2 100.9 mm2 428.7 mm2 25.2 mm2
Mathematics
2 answers:
Scorpion4ik [409]3 years ago
7 0

Answer: the answer is c 428.7mm^2

Step-by-step explanation:

Marat540 [252]3 years ago
5 0

Answer:

428.7 mm²

Step-by-step explanation:

The area (A) of the sector is calculated as

A = area of circle × fraction of circle

   = πr² × \frac{170}{360}

   = π × 17² × \frac{17}{36}

   = 289π × \frac{17}{36}

   = \frac{289(17)\pi }{36} ≈ 428.7 mm²

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a + b ≥ 30,  b ≥ a + 10, the system of inequalities could represent the values of a and b

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<u>Step-by-step explanation:</u>

Here we have , The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is the greater integer, We need to find which system of inequalities could represent the values of a and b . Let's find out:

Let two numbers be a and b where b>a . Now ,

  • The sum of two positive integers, a and b, is at least 30

According to the given statement we have following inequality :

⇒ a+b\geq 30

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According to the given statement we have following inequality :

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