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BARSIC [14]
2 years ago
6

Simplify: sin^2xcos^2x-cos^2x

Mathematics
1 answer:
shtirl [24]2 years ago
8 0

Answer:

-cos^4(x)

Step-by-step explanation:

Step 1: Use the Pythagorean identity : 1=cos^2(x) + sin^2(x)

1-sin^2(x) = cos^2(x)

-1+sin^2(x) = -cos^2(x)

cos^2(x) (-cos^2(x))

Step 2: Factor out common terms cos^2(x)

cos^2(x) (sin^2(x)-1)

Ans: -cos^4(x)

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Jorge has a loan of $25,230. This loan
Fed [463]

Answer:

D. $26,743.80

Step-by-step explanation:

25230(1+ .06(1))

type that in a calculator and you will get the correct answer of D.

Also I literally learned this 5 minutes ago and my teacher said I was correct.

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=-3%5Csqrt%7B45y%C2%B3%7D" id="TexFormula1" title="-3\sqrt{45y&sup3;}" alt="-3\sqrt{45y&sup3;}"
GarryVolchara [31]

Answer:

-9A · √(5yA)

Step-by-step explanation:

The coefficient -3 stays the same.

45 factors into 5·9, which is helpful because 9 is a perfect square.

Thus, √45 = 3√5.

y cannot be factored.  It stays under the radical.

A³ can be factored into A² (a perfect square) and A.

Thus,

-3√(45yA³) = -3 · 3√5 · √y · A · √A, or

                   = (-3)(3)(A) · √(5yA), or

                    = -9A · √(5yA)

4 0
3 years ago
What formula should be used to find the circumference of a circle
Inessa05 [86]
The circumference = π x the diameter of the circle (Pi multiplied by the diameter of the circle). Simply divide the circumference by π and you will have the length of the diameter. The diameter is just the radius times two, so divide the diameter by two and you will have the radius of the circle
3 0
3 years ago
Read 2 more answers
(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this
Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta

Simplify. The denominator uses the difference of two squares pattern:

\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta

Split into two separate fractions:

\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta

Rewrite the two fractions:

\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=}  \sec^2\theta - \sec\theta\tan\theta

Hence verified.

8 0
3 years ago
((16 - (4/2))^2) × 3 =
VARVARA [1.3K]

Answer:

588

Step-by-step explanation:

((16 - (4/2))^2) × 3      Simplify the inner parentheses

((16 - 2)^2) x 3     Solve inner parentheses again

((14)^2) x 3        Solve exponents

196 x 3      Multiply

588

7 0
3 years ago
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