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Dmitrij [34]
3 years ago
15

Please help me with this trigonometry question:

Mathematics
1 answer:
zzz [600]3 years ago
8 0

Answer:

The distance from A to B is 736.2 to the nearest tenth foot

Step-by-step explanation:

In ΔCAB

∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A

∴ m∠CAD = m∠ACB + m∠ABC

∵ m∠ABC = 20°

∴ m∠ACB = 30° - 20° = 10°

We will use the sin rule to find the distance AB

∵ \frac{sin20}{1450}=\frac{sin10}{AB}

∴ AB=\frac{1450(sin10)}{sin20}=736.1842936 ≅ 736.2 to the nearest tenth foot

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Step by step:

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Answer:

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Step-by-step explanation:

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Given the general form of the sinusoidal function, y = AsinB(x - C) + D, match the following items.
Jet001 [13]

Answer:

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\omega = B (Angular frequency) (Correct answer: 2)

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Step-by-step explanation:

The general form of a sinusoidal function is represented by the following characteristics:

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Where:

\Delta y - Amplitude.

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y_{o} - Vertical shift.

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T = \frac{2\pi}{\omega}

By direct comparison, we get the following conclusions:

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\omega = B (Angular frequency) (Correct answer: 2)

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y_{o} = D (Vertical shift) (Correct answer: 4)

\frac{2\pi}{\omega} = \frac{2\pi}{B} (Period) (Correct answer: 5)

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Step-by-step explanation:

you need a picture to further understand and answer the question right

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