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Phantasy [73]
2 years ago
11

A group of preschoolers has 8 boys and 24 girls. What is the ratio of girls to all children? Show your work.

Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
4 0
24:32
Because there are 24 girls out of 32 kids total including the 8 boys
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On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite direction. The numb
vfiekz [6]

Answer:

b

Step-by-step explanation:

5 0
3 years ago
Enter the solutions from least to greatest. (2x +4)(3x -2)=0
morpeh [17]

Answer:

From least to greatest: -2, 2/3

Step-by-step explanation:

Set each factor equal to 0 and solve

2x + 4 =0

2x = -4

x = -2

3x - 2 = 0

3x = 2

x = 2/3

The solutions are -2 and 2/3

7 0
3 years ago
Kyra has 2 plates, 2 cups, and 2 bowls. If she chooses one of each randomly, what is the probability that the plate, cup, and bo
tensa zangetsu [6.8K]
The correct answer is A. <span>0.125
</span><span>
1/8(this is a fraction)</span>
(divide the numerator by the denominator)

1÷8 = 0.125
If you want you can Convert the number to a percentage:<span>
0.125×100=12.5%

but the question is asking for decimal form therefore the answer is </span>0.125.
I also did the quiz and this was correct

Hope this helps!! :D
7 0
2 years ago
Read 2 more answers
CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
Rufina [12.5K]

Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

Edit: Small Mistake :)

5 0
2 years ago
How many solutions does the system of equations have 2x = -10y + 6 and x + 5y = 3
kipiarov [429]
Infinite

x=-5y+3 is the same as x+5y=3
3 0
3 years ago
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