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bogdanovich [222]

2 years ago

7

HELP PLEASE I BEG U - 10MIN LEFT

1 answer:

Anni [7]2 years ago

7 0

The base is 5 units and the height is 9 units.

Base:

-4 to 1

=====

1 -(-4)

<u>5 units</u>

Height:

-1 to 8

=====

8 -(-1)

8 + 1

<u>9 units</u>

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Describe the graph of y = 3x and compare it with the graph of y = x,

kykrilka [37]

check math way

Step-by-step explanation: it helps more then here

7 0

3 years ago

H=-5 and w=2, work out the value of 4h-3w

olganol [36]

You would simply have to plug in, or substitute, the given values in the equations.

So, H=-5, W=2 and the problem is 4h-3w

To plug them in, your new equation would be 4(-5)-3(2) and simplify. So it becomes -20-6 which = -26.

And -26 would be your answer.

3 0

4 years ago

Read 2 more answers

On the scale drawing of a car, the length from bumper to bumper is 6 inches. The car’s actual length, from bumper to bumper, is

dimulka [17.4K]

Answer:

3/8 in/ft
1/32 . . . (pure number, no units)

Step-by-step explanation:

The ratio can be expressed directly as ...

... (6 in)/(16 ft) = 3/8 in/ft

This can be read or used in different ways:

3/8 in = 1 ft
3 in = 8 ft

Or, the units can be made compatible and the ratio expressed as a pure number.

... (1/2 ft)/(16 ft) = (1/32) ft/ft = 1/32

This means whatever measurement is made on the model, the actual vehicle measurement is 32 times that.

4 0

4 years ago

A sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters. Give a point est

xxTIMURxx [149]

Answer:

Point estimate for the population variance = 3.92 * $10^{-3}$ .

Step-by-step explanation:

We are given that a sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters ;

X X - $Xbar$ $(X-Xbar)^{2}$

1.13 1.13 - 1.188 = -0.058 3.364 * $10^{-3}$

1.15 1.15 - 1.188 = -0.038 1.444 * $10^{-3}$

1.15 1.15 - 1.188 = -0.038 1.444 * $10^{-3}$

1.24 1.24 - 1.188 = 0.052 2.704 * $10^{-3}$

1.27 1.27 - 1.188 = 0.082 <u> 6.724 * </u> $10^{-3}$ <u> </u>

$\sum (X-Xbar)^{2}$ <u>= 0.01568 </u>

Firstly, Mean of above data, $Xbar$ = $\frac{\sum X}{n}$ = $\frac{1.15+1.24+1.15+1.27+1.13}{5}$ = 1.188

Point estimate of Population Variance = Sample variance

= $\frac{\sum (X-Xbar)^{2}}{n-1}$ = $\frac{0.01568}{4}$ = 3.92 * $10^{-3}$ .

Therefore, point estimate for the population variance = 3.92 * $10^{-3}$ .

5 0

3 years ago

Read 2 more answers

help with these all no links- I MEAN IT! and no oh i just came for the points cr_ap brainlyest if correct

natka813 [3]

Answer:

#1

Least value = 5

#2

Median = 56, option C

#3

Median = 113, option C

#4

A = 10, the minimum point

#5

Q1 = 99.5, the median of the lower half of data, option C

7 0

3 years ago