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kiruha [24]
3 years ago
13

Which system of equations would have no solution? pls helpp

Mathematics
2 answers:
Leya [2.2K]3 years ago
6 0

Answer:

3x+y=8 and 3x+y=9

Step-by-step explanation:

Assume these two equations:

a1x+b1y+c1=0

a2x+b2y+c2=0

If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.

In these case, take a look at the last option:

3x  + y = 8 \\ 3x + y = 9

Re-write 'em as a standard form:

3x  + y - 8 = 0 \\ 3x + y - 9 = 0

So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:

\frac{3}{3}  =  \frac{1}{1}  ≠ \frac{ - 8}{ - 9}

And they do not have any collision point

Likurg_2 [28]3 years ago
3 0

Answer:

Give the person above me brainliest, they are correct.

Step-by-step explanation:

Have a wonderful rest of your day or night! ^w^

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