Question

Which system of equations would have no solution? pls helpp

Answer 1

Answer:

3x+y=8 and 3x+y=9

Step-by-step explanation:

Assume these two equations:

a1x+b1y+c1=0

a2x+b2y+c2=0

If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.

In these case, take a look at the last option:

$3x + y = 8 \\ 3x + y = 9$

Re-write 'em as a standard form:

$3x + y - 8 = 0 \\ 3x + y - 9 = 0$

So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:

$\frac{3}{3} = \frac{1}{1} ≠ \frac{ - 8}{ - 9}$

And they do not have any collision point

Answer 2

Answer:

Give the person above me brainliest, they are correct.

Step-by-step explanation:

Have a wonderful rest of your day or night! ^w^