It uses elimination againLet A be 15% juice and B is 5% juice
A+B = 100.15A + 0.05B = 0.11*10 = 1.1Multiply 2nd equation by 100 to get rid of decimals
A+B = 1015A + 5B = 110
Hello!
On the periodic table, as we go down the periodic table, the ionization energy decreases, but as we go across the periodic table (left to right), the ionization increases.
On the periodic table, lithium (Li) is located in column one, beryllium (Be) is located in column two, and (B) boron is located in column 13. As stated above, when we go across the periodic table (left to right), the ionization increases.
Therefore, the element with the highest ionization energy is Boron, or symbol B on the period table.
Answer:
The correct option is: a. reversible reaction
Explanation:
In thermodynamics, Gibb's free energy is the quantitative measure of the <u>spontaneity or feasibility </u>of a chemical reaction, at fixed temperature and pressure.
It can also be described as the <u>maximum available work obtained from a closed system</u>. This maximum work can only be achieved in a reversible process, <u>at fixed pressure and temperature.</u>
<u>The Gibb's free energy (ΔG) is given by</u>: ΔG = ΔH - T.ΔS
Answer:
pH = 3.65
Explanation:
given data
pKa of HNO2 = 3.40
nitrous acid (HNO2) = 0.110 M
NaNO2 = 0.200 M
to find out
What is the pH
solution
we get here ph for acidic buffer that is express as
pH = pKa + log(salt÷acid) ........................1
put here value and we get
pH = 3.40 + log(0.200÷0.110)
pH = 3.65
First, we need to calculate the principal quantum number n for this electron, using the equation:
E = (-13.60 eV) / (n x n)
where E is the energy that is used to bound the electron (here, E = - 0.544 eV).
- 0.544 eV = (-13.60 eV) / (n x n)
n x n = (- 13.60 eV) / (- 0.544 eV)
n x n = 25
n = 5
The orbital radius that is equal to the radius of a hydrogen atom is calculated using the equation:
r = 0.053 nm x n x n
r = 0.053 nm x 5 x 5
r = 0.053 nm x 25
r = 1.325 nm
