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Vika [28.1K]
2 years ago
6

PLEASE HELP: You have been given 2.42 moles of beryllium sulfide (BeS), determine the mass in grams of beryllium sulfide that yo

u have.

Chemistry
1 answer:
Alecsey [184]2 years ago
3 0

The mass in grams of the given beryllium sulfide is 99.2 g. The correct option is the second option - 99.2 g BeS

<h3>Calculating mass of a compound </h3>

From the question, we are to determine the mass of the given beryllium sulfide.

From the given information,

Number of moles of beryllium sulfide (BeS) given = 2.42 moles

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of BeS = 41 g/mol

Then,

Mass of BeS = 2.42 × 41

Mass of BeS = 99.22

Mass of BeS ≅ 99.2 g

Hence, the mass in grams of the given beryllium sulfide is 99.2 g. The correct option is the second option - 99.2 g BeS

Learn more on Calculating mass of a compound here: brainly.com/question/18142599

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<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2C_2O_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

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Putting values in above equation, we get:

2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

Given mass of oxalic acid = ? g

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Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g

Hence, the mass of original oxalic acid sample is 6.75 grams

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