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Diano4ka-milaya [45]
3 years ago
8

Mary wanted to determine which type of fertilizer would help her plants grow taller. She got 16 plant pots andd scooped 2 cups o

f the same type of soil in each. Then she planted 1 sunflower seed in each plant pot. The first four pots were placed in her garden to grow. No fertilizer was added to this group. Mary did this to see how tall sunflower plants would grow under normal conditions. In the next four pots she added Miracle Grow. In the four pots she added Grow Rite and the last four pots she added Perlite. She placed all the plant pots in the same are of the garden.
How many trials were conducted?
Chemistry
1 answer:
Natali5045456 [20]3 years ago
3 0

Mary conducted four trials:

1. One with no fertilizer

2. One with Miracle Grow

3. One with Grow Rite

4. One with Perlite

She used four pots per trial, for a total of 16 pots.

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What trend does the first ionization energy follow, going down the periodic
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Explanation:

Ionization energy trend along group:

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How many grams of FeCo3 will be produced from 57.2g FeCl2
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Answer:

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Solution:

The Balance Chemical Equation is as follow,

                           FeCl₂ + Na₂CO₃    →    FeCO₃ + 2 NaCl

Step 1: Calculate Mass of FeCl₂ as,

                            Molarity  =  Moles ÷ Volume

Solving for Moles,

                            Moles  =  Molarity × Volume

Putting Values,

                            Moles  =  2 mol.L⁻¹ × 1.24 L

                           Moles  =  2.48 mol

Also,

                            Moles  =  Mass ÷ M.Mass

Solving for Mass,

                            Mass  =  Moles × M.Mass

Putting Values,

                            Mass  =  2.48 mol × 126.75 g.mol⁻¹

                            Mass =  314.34 g of FeCl₂

Step 2: Calculate Mass of FeCO₃ formed as,

According to equation,

          126.75 g (1 mole) FeCl₂ produces  =  115.85 g (1 mole) FeCO₃

So,

               314.34 g of FeCl₂ will produce  =  X g of FeCO₃

Solving for X,

                     X =  (314.34 g × 115.85 g) ÷ 126.75 g

                     X =  287.30 g of FeCO₃

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