All categories

2 years ago

Missing angle - circle theorem / PLEASE HELP

Mathematics

2 answers:

user100 [1]2 years ago

4 0

Answer:

D. 20°

Step-by-step explanation:

just do an elimination, since 52° is big then X it obviously can't be 96°. And that leaves us with 32° and 20°. As you can see 32° is bigger than X then it's 20° ♡

xxMikexx [17]2 years ago

3 0

Answer:

Step-by-step explanation:

angles on the circumference of a circle subtended on the same arc are congruent , then

x = 52°

You might be interested in

Each day Marvin exercises for 48 minutes how many days will it take him to exercise for 576 minutes?

Triss [41]

The answer is 12 because 576 divided 48 is 12 .

8 0

3 years ago

Read 2 more answers

hmu if ur bored and wana talk. age limit tho. cant be younger than 14 or older than 19 dont wanna talk to creepy people lol

Orlov [11]

Answfunny lol lol

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Consider the equations 15x + 9y = 45 and 9x + 8y = 12. Solve the system of equations using elimination. Give your solution to th

True [87]

Answer:

(-5.77, 6.46)

Step-by-step explanation:

15x + 9y = 45 ----------- i

9x + 8y = 12----------------ii

Multiply equation i by 9 the coefficient of x in equ ii

And equation ii by 15 the coefficient of x in equ I

9 x 15x + 9y = 45 ----------- i

15 x 9x + 8y = 12----------------ii

135x+81y = 405

135x+120y= 180

Subtract equation ii from I

135x-135x+81y-(+120y)= 405-180

-39y=225

y = 225/-39 = -5.77

Insert the value of y in equ i

15x + 9y = 45

15x+9(-5.77) = 45

15x-51.92=45

15x = 45+51.92

15x= 96.92

x = 96.92/15= 6.46

(x,y) = (-5.77, 6.46)

x = 6.92/15

5 0

3 years ago

Find the midpoint of (0, 4) and (2, -2)

lidiya [134]

Answer:

$\text{Midpoint} = (1, \; 1)$

Step-by-step explanation:

$M = (x_M, \; y_M)$

$M = \left(\dfrac{x_1 + x_2}{2}, \; \dfrac{y_1 + y_2}{2}\right)$

$M = \left(\dfrac{0 + 2}{2}, \; \dfrac{4 + -2}{2}\right)$

$M = \left(\dfrac{2}{2}, \; \dfrac{2}{2}\right)$

$M = (1, \; 1)$

5 0

2 years ago

Read 2 more answers

Given: the function defined by f(x)=3x^2-4 Which statement is true? 1. f(0) = 0 2. f(-2) = f(2) 3. f(5)+ f(2) = f(7) 4. f(5) x f

sergeinik [125]

$f(x)=3x^2-4 \\ \Downarrow \\ f(0)=3 \times 0^2-4=0-4=-4 \\ -4 \not= 0 \\ f(0) \not= 0 \\
\hbox{statement 1 is false} \\ \\
f(-2)=3 \times (-2)^2-4 =3 \times 4-4=12-4=8 \\
f(2)=3 \times 2^2-4=3 \times 4-4=12-4=8 \\ 8=8
\\ f(-2)=f(2) \\
\hbox{statement 2 is true}$

$f(5)=3 \times 5^2-4=3 \times 25-4=75-4=71 \\ f(2)=8 \\
f(7)=3 \times 7^2-4=3 \times 49-4=147-4=143 \\
71+8 \not= 143 \\
f(5)+f(2) \not= f(7) \\ \hbox{statement 3 is false} \\ \\
f(5)=71 \\ f(2)=8 \\ f(10)=3 \times 10^2-4=3 \times 100-4=300-4=296 \\
71 \times 8 \not= 296 \\
f(5) \times f(2) \not= f(10) \\
\hbox{statement 4 is false}$

Stamement 2. f(-2)=f(2) is true.

3 0

3 years ago