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3 years ago

Transform the kilometers into percentages pls

Mathematics

1 answer:

bazaltina [42]3 years ago

4 0

Percentages? Are you sure that’s not a mistake

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A line passes through the point (0,6) and is parallel to the line with the equation y =

Tresset [83]

Answer:

First option is the correct choice.

Step-by-step explanation:

y - 6 = 1/5 x + 0

y = 1/5x + 6

Best Regards!

8 0

2 years ago

Read 2 more answers

An isosceles triangle △ABC with the base BC is inscribed in a circle. Find the measures of angles of the triangle, if measure of

____ [38]

Answer:

angle at A: 51°
base angles: 64.5°

Step-by-step explanation:

The measure of the inscribed angle BAC is half the measure of the intercepted arc BC, so is 102°/2 = 51°.

The base angles at B and C are the complement of half this value, or ...

90° -(51°/2) = 64.5°

The angle measures in the triangle are ...

∠A = 51°

∠B = ∠C = 64.5°

6 0

3 years ago

What is the slope-intercept equation of the line below? y - i ntercept = (0, - 4) slope = 3

Artist 52 [7]

Answer:

y = 3x -4

Step-by-step explanation:

The slope-intercept equation looks like this: $y = mx +b$ . Where m is the slope of the function and b is the y-coordinate of the vertical intercept (where the function crosses the y-axis). Let's apply the formula:

$y = mx +b$

$y = 3x +(-4)$

$y = 3x -4$

4 0

2 years ago

8+4(s-4t) simplify the expression. HELP, 20 POINTS

ella [17]

8+ 4s -16t= 4 (2+s-4t)

5 0

3 years ago

A, B and C are events such that P(A) = 1/3, P(B) = ¼, and P(C) = 1/5. Find P(AUBUC) under each of the following assumptions: a)

marta [7]

(a) If $A,B,C$ are mutually exclusive, then

$P(A\cap B)=P(A\cap C)=P(B\cap C)=P(A\cap B\cap C)=0$

so we have

$P(A\cup B\cup C)=P(A)+P(B)+P(C)=\dfrac{47}{60}$

(b) If $A,B,C$ are mutually independent, then

$P(A\cap B)=P(A)P(B),$

$P(A\cap C)=P(A)P(C),$

$P(B\cap C)=P(B)P(C),$

$P(A\cap B\cap C)=P(A)P(B)P(C)$

so that

$P(A\cup B\cup C)=P(A)+P(B)+P(C)-(P(A\cap B)+P(A\cap B)+P(B\cap C))+P(A\cap B\cap C)$

$P(A\cup B\cup C)=\dfrac{47}{60}-\left(\dfrac1{12}+\dfrac1{15}+\dfrac1{20}\right)+\dfrac1{60}$

$P(A\cup B\cup C)=\dfrac35$

5 0

3 years ago