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2 years ago

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What is the product of (2x-7) and (3x + 3)?

1 answer:

eduard2 years ago

3 0

<h3>✒️EVALUATION </h3>

==================================

$\large\sf\underline{Problem:}$

What is the product of (2x-7) and (3x + 3)?

A. 6x2 + 15x-21
B. 6x2 - 15x - 21
C. 6x2 + 15x + 21
D. 6x2 - 15x + 21

==================================

$\large\sf\underline{Answer:}$

$\qquad \qquad \huge \rm Letter\:B.$

*Please read and understand my solution. Don't just rely on my direct answer*

==================================

$\large\sf\underline{Solution:}$

Here we have the given choices:

A. 6x2 + 15x-21
B. 6x2 - 15x - 21
C. 6x2 + 15x + 21
D. 6x2 - 15x + 21

Solve this equation using the distributive property,where you multiply each term to get the number.

$\begin{gathered} \rm2x - 7 = \boxed{ 6} \: \bigg| \small\boxed{\: 6 {x}^{2} } \\ \rm (7)(3) = \boxed{21} \bigg | \boxed{\: 21 x} \\ \\ \qquad \rm6x^{2}+(6x- 21x)-21 \\ \qquad \boxed{ \rm6 {x}^{2} + 15x - 21}\end{gathered}$

Therefore, the correct option is letter B.

==================================

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Range of f(x) is all real numbers except 2.

Step-by-step explanation:

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Vertical and horizontal asymptote, domain, range and roots of f(x).

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First of all, let us find the roots of f(x).

<em>Roots of f(x) means the value of x where f(x) = 0</em>

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Domain of f(x) i.e. the values that we give as input to the function and there is a value of f(x) defined for it.

For x = 3, the value of f(x) $\rightarrow \infty$

For all, other values of $x$ , $f(x)$ is defined.

Hence, Domain of f(x) is all real numbers except 3.

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It is possible only when

$x-3=0\\\Rightarrow x=3$

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Please refer to the graph of given function as shown in the attached image.

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