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lord [1]
3 years ago
12

The value -1 is a lower bound for the zeros of the function shown below F(x)=x^4+x^3-11x^2-9x+18

Mathematics
1 answer:
Rama09 [41]3 years ago
8 0
Hello,

f(x)=x^4+x^3-11x²-9x+18=(x+2)(x+3)(x-3)(x-1)

-3 is the lowest zero.

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Problem Page
MrMuchimi

Answer:

1 machine must be made to minimise the unit cost.

Step-by-step explanation:

<em>Step 1: Identify the function</em>

x is the number of machines

C(x) is the function for unit cost

C (x) = 0.5x^2-150 + 21,035

<em>Step 2: Substitute values in x to find the unit cost</em>

C (x) = 0.5x^2-150 + 21,035

The lowest value of x could be 1

To check the lowest cost, substitute x=1 and x=2 in the equation.

<u>When x=1</u>

C (x) = 0.5x^2-150 + 21,035

C (x) = 0.5(1)^2-150 + 21,035

C (x) = 20885.5

<u>When x=2</u>

C (x) = 0.5x^2-150 + 21,035

C (x) = 0.5(2)^2-150 + 21,035

C (x) = 20887

<em>We can see that when the value of x i.e. the number of machines increases, per unit cost increases.</em>

Therefore, 1 machine must be made to minimise the unit cost.

!!

3 0
3 years ago
. What is the solution set for
elena-s [515]

Answer:

Hope this is correct and helpful

HAVE A GOOD DAY!

4 0
3 years ago
Use the discriminant to describe the roots of each equation. Then select the best description.
IrinaK [193]
\frac{-b+- \sqrt{b^{2} -4ac }  }{2a}
This is the solution of the equation, where a=1, b=-5, c=7

So the discriminant is : 
b^2-4ac=25-4*7= -3
The square root of -3 is non-real, this both solutions are non-real. 
3 0
3 years ago
Read 2 more answers
A prime number less than 100 is selected randomly. what is the probability that its square has units digit $7$?
liberstina [14]
Any number ends with 0, 1, 2, 3, 4, 5, 6, 7, 8 or  9

Given any number. The square of this number is the last digit of square of the original numbers units digit.

For example

23*23 ends with 9 (3*3=9)

149*149 ends with 1 (9*9=81)

2564*2564 ends with 6 (4*4=16) 

and so on

so all the possible unit digits of a square number are {0, 1, 4, 5, 6, 9}

because:

0*0= 0 ; 1*1=1; 2*2=4; 3*3=9; 4*4=16; 5*5=25, 6*6=36; 7*7=49; 8*8=64, 9*9=81

Thus, the probability that the square of a number selected from any set of numbers being 7, is 0.


Answer: 0
 

4 0
3 years ago
4 1/5 ÷ 2/3 as a mixed number in simplest form
Lady_Fox [76]

Answer:

<h2>6 \frac{3}{10}</h2>

Step-by-step explanation:

4 \frac{1}{5}  \div  \frac{2}{3}  =  \frac{21}{5}  \div  \frac{2}{3}  =  \frac{21}{5}  \times  \frac{3}{2 }  \\  \\  =  \frac{63}{10}  = 6 \frac{3}{10}

8 0
3 years ago
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