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Oxana [17]
2 years ago
12

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE AND PLEASE EXPLAIN WHY THAT IS THE ANSWER

Mathematics
1 answer:
nekit [7.7K]2 years ago
7 0

Answer:

1 - 60

2 - 120

3 - 60

4 - 120

5 - 60

6 - 120

7 - 60

8 - 120

Step-by-step explanation:

Via supplementary angles, you can conclude that angle 5 is 60. Because of vertical angles, angle 8 is 120 and angle 7 is 60. Because of alternate exterior angles, angle 1 is congruent to angle 7 and angle 2 is congruent to angle 8, meaning angle 1 is 60 and angle 2 is 120. Because of vertical angles, angle 3 is 60 and angle 4 is 120.

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Li had 5 2/3 gallons of juice. He served 2 3/4 gallons at breakfast. How many gallons does Li have left? Enter your answer in th
Sholpan [36]

Total quantity of juice Li had = 5 2/3 gallons.

In breakfast used quantity = 2 3/4 gallons.

Number of gallons of juice does Li have left = Total quantity - used quantity.

Therefor, number of gallons of juice does Li have left = 5 2/3 gallons - 2 3/4 gallons.

Let us convert those mixed fractions into improper fracions first.

5 2/3 = (5*3+2)/3 = 17/3.

2 3/4 = (2*4+3)/4 = 11/4.

5 2/3 gallons - 2 3/4 gallons = 17/3 -11/4.

Subtracting fractions by taking common denominator (lcd).

We have common denominator of 3 and 4 = 3*4 = 12.

So, 17/3 -11/4 = 17*4/3*4 - 11*3/4*3

= 68/12 - 33/12.

= (68-33)/12.

= 35/12

Let us convert 35/12 into mixed fraction now.

Dividing 35 by 12 we get quotient 2 and remainder 11.

So, 35/12 can be wriiten in mixed fractions as 2 11/12.

And final answer would be, Li have left 2 11/12 gallons.

7 0
3 years ago
What is a requirement of adjacent angles?
vlada-n [284]

Answer:

Step-by-step explanation:

Two angles are Adjacent when they have a common side and a common vertex (corner point) and don't overlap.

7 0
3 years ago
Find all solutions of the equation in the interval [0, 2pi).
lozanna [386]

Answer:

543

Step-by-step explanation:

8 0
3 years ago
Here, thankyou!!!!!!!
FromTheMoon [43]

Answer:

Perimeter of i - 22CM

Area of i - 13CM^2

Perimeter of ii -38CM

Area of ii -66CM^2

Perimeter of iii -30CM

Area of iii- 42CM^2

Perimeter of iv - 50CM

Area of iv- 126CM^2

Step-by-step explanation:

SHAPE I:

PERIMETER = S + S + S + S + S +S

= 7 + 1 + 5 +3 +4 +2

= 22CM

AREA = Part a - 4 * 2 = 8cm^2 part B - 5 *1 = 5cm^2

Total = 8 + 5 = 13cm^2

SHAPE II:

PERIMETER = S + S + S + S + S +S

= 4 + 4 +5 + 6 + 9 + 10

= 38 CM

AREA = Part a - 5 * 10 = 50 cm^2 part B - 4 *4 =16 cm^2

Total = 50+16 =66 cm^2

SHAPE III:

PERIMETER = S + S + S + S + S +S

= 9 + 2 + 3 + 4 + 6 + 6

= 30CM

AREA = Part a - 6 * 6 = 42cm^2 part B - 3 * 2= 6cm^2

Total = 36 + 6 =42 cm^2

SHAPE IV:

PERIMETER = S + S + S + S + S +S

= 9 + 10 + 4 + 6 + 6 + 15

= 50 CM

AREA = Part a -15 * 6 = 90 cm^2 part B - 9 *4 = 36cm^2

Total = 90 + 36 = 126cm^2

HOPE THIS HELPED

6 0
3 years ago
A friend tells you that he has a cubic equation with exactly three complex roots. Determine which explanation best explains why
Ksju [112]
Complex solutions, namely roots with a √(-1) or "i" in it, never come all by their lonesome, because an EVEN root like the square root, can have two roots that will yield the same radicand.

a good example for that will be √(4), well, (2)(2) is 4, so 2 is a root, but (-2)(-2) is also 4, therefore -2 is also a root, so you'd always get a pair of valid roots from an even root, like 2 or 4 or 6 and so on.

therefore, complex solutions or roots are never by their lonesome, their sister the conjugate is always with them, so if there's a root a + bi, her sister a - bi is also coming along too.

if complex solutions come in pairs, well, clearly a cubic equation can't yield 3 only.
3 0
3 years ago
Read 2 more answers
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