Answer:
128 deg
Step-by-step explanation:
The sum of the measures of the angles of a polygon of n sides is
(n - 2)180
A trapezium has 4 sides, so the sum of the measures of the angles is
(4 - 2)180 = 2(180) = 360
<em>m<CBE + m<C + m<D + m<DEB = 360</em>
Angles ABC and CBE are a linear pair so the sum of their measures is 180 deg.
m<ABC + m<CBE = 180
115 + m<CBE = 180
m<CBE = 65
m<C = x
m<D = 90
Angles DEB and DEF are a linear pair so the sum of their measures is 180 deg.
m<DEB + m<DEF = 180
m<DEB + m<103 = 180
m<DEB = 77
<em>m<CBE + m<C + m<D + m<DEB = 360</em>
65 + x + 90 + 77 = 360
x + 232 = 360
x = 128
Answer: 128 deg
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Answer:
Step-by-step explanation:
#1 second line: x-y=-3
x=y-3(isolating x to prepare for substitution)(what x is equivalent to)
get back to the first line
x+y=5
(y-3)+y=5(substituting the value of x of the first line with the value of x at the second line)(It is a process to find the intersection between the two lines(line#1 and line#2 are two linear functions)
2y-3=5(simplify)
2y=8(simplify)
y=4(simplify)
line#1 x+y=5
x+(4)=5(plug the value of y back into either line#1 or line#2 will work)(plugging in the y value of the point of intersection to solve for the x value of the point of intersection)
x=1(solve)
the two linear lines intersect at the point(1(x coordinate), 4(y coordinate))(1,4)
#2 (line#1) y=3x-1
(line#2) 2x+y=14
2x+(3x-1)=14
5x-1=14
5x=15
x=3
y=3(3)-1
y=9-1
y=8
(3,8)
#3 line#1 2x+3y=8
line#2 6x+9y=24
2x=8-3y
x=(8-3y)/2
6((8-3y)/2)+9y=24
24-9y+9y=24
24=24
(those two lines are on top of yeach other/the same line)
any point on the line
#4 line#1 3x-4y=12
line#2 y=3/4x-4
3x-4(3/4x-4)=12
3x-3x+16=12
16=12
parallel lines: lines with same slope and different y-intercept
No solution/they never intercept each other
I hope it is helpful, if you have any question, I will answer ASAP
Answer:
it's a terminating decimal
<span> 2 (a+4)+6a=48
2a + 8 + 6a = 48
8a = 40
a = 5</span>
