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2 years ago

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A taxi ride costs $3 plus $2.50 per mile. Write and graph an equation in two variables that represents the total cost of a taxi

ride. Let m represent number of miles and represent the total cost (in dollars) of the taxi ride.
Equation: c=

1 answer:

Neporo4naja [7]2 years ago

6 0

Answer:

C = 3 + 2.5M

Step-by-step explanation:

2.5

x

M

2.5M

+

3 =

3 + 2.5M

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A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,

katovenus [111]

Answer:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation

$X_{1}=45$ represent the number of correct answers for university degree holders

$X_{2}=57$ represent the number of correct answers for university non-degree holders

$n_{1}=373$ sample 1 selected

$n_{2}=639$ sample 2 selected

$p_{1}=\frac{45}{373}=0.121$ represent the proportion of correct answers for university degree holders

$p_{2}=\frac{57}{639}=0.0892$ represent the proportion of correct answers for university non-degree holders

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

7 0

3 years ago

Solve for b.<br> r = (b-5)m

alukav5142 [94]

Answer:

b=5m+r/m

Step-by-step explanation:

Let's solve for b.

r=(b−5)(m)

Step 1: Flip the equation.

bm−5m=r

Step 2: Add 5m to both sides.

bm−5m+5m=r+5m

bm=5m+r

Step 3: Divide both sides by m.

bm/m=5m+r/m

b=5m+r/m

Answer:

b=5m+r/m

6 0

2 years ago

Read 2 more answers

Emerson has an associate degree. Based on the bar chart below, how will his employment opportunities change from 2008-2018?

ANEK [815]

Answer:

19% change

Step-by-step explanation:

Since, Emerson has an associate degree,

His employment is 19% changed in 10 years, i.e. from 2008 to 2018.

Because the bar graph shown the percentage of change in employment from 2008 to 2018.

Also, Employment of associate degree is most affected in 10 years.

And those who have job training and work experience is least affected in these 10 years.

5 0

3 years ago

Help please first with the right answer will be marked brainlyest

andre [41]

I believe this is correct

5 0

3 years ago

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What is the answer to this math question

Vilka [71]

$(19 {b}^{3} + 16 {f}^{3} ) \times 2 {b}^{5} = 38 {b}^{8} + 32 {b}^{5} {f}^{3}$

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2 years ago