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klio [65]
3 years ago
11

Find f(-2) for the following function. f(x)=3.6x-2​

Mathematics
1 answer:
butalik [34]3 years ago
4 0

Answer:

f(- 2) = - 9.2

Step-by-step explanation:

To evaluate f(- 2) substitute x = - 2 into f(x) , that is

f(- 2) = 3.6(- 2) - 2 = - 7.2 - 2 = - 9.2

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antoniya [11.8K]

Answer:

92.5 cm²

Step-by-step explanation:

Lets take this step by step

Bottom rectangle is 2 by 5, so then 2*5 = 10

Large rectangle is 8 by 9, so 8*9 = 72

The triangle is 7 by 3, you get the 7 by subtracting the 5 side from the square because using the square you can tell that the height is 9 - something.

The 5 you get is from subtracting the cut part that you might have made because the height of that is 2, therefore you cut off 2 from 7 making it 5

Triangle area is h*b / 2, therefore 7*3 = 21/2 = 10.5

Add them all together, 10.5 + 10 + 72 and you get 92.5

6 0
4 years ago
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Helppp I will make u a brainlist!!
adelina 88 [10]

Answer:

Answer 2

Step-by-step explanation:

the number are being added together based on their position

3 0
3 years ago
Read 2 more answers
Help please please!!!!!
IgorLugansk [536]

Answer:

x=28

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Integration using part formula<br> <img src="https://tex.z-dn.net/?f=%5Cint%5Climits%20%7Bx%5Enlogx%7D%20%5C%2C%20dx" id="TexFor
liq [111]

Answer:

Integration of I= \int {x^{n}logx \, dx=[\frac{logx}{n+1} x^{(n+1)}]-[\frac{1}{(n+1)^{2}}x^{(n+1)}]

Step-by-step explanation:

Given integral is I= \int {x^{n}logx \, dx

Take logx=t

x=e^{t}

x^{n}=e^{nt}

\frac{1}{x} dx=dt

dx=xdt

dx=e^{t}dt

I= \int (e^{nt})(t)(e^{t})\, dt

I= \int (e^{(n+1)t})(t)\, dt

Using integration by part,

I= (t)\int [e^{(n+1)t}]\, dt-\int[\frac{d}{dt}{t}\times\int (e^{(n+1)t})]\\\\I= (t) [\frac{1}{n+1}e^{(n+1)t}]-\int[1\times\frac{1}{n+1}e^{(n+1)t}]\,dt\\\\I=[\frac{t}{n+1}e^{(n+1)t}]-[\frac{1}{(n+1)^{2}}e^{(n+1)t}]

Writing in terms of x

I=[\frac{t}{n+1}e^{(n+1)t}]-[\frac{1}{(n+1)^{2}}e^{(n+1)t}]

I=[\frac{logx}{n+1}e^{(n+1)logx}]-[\frac{1}{(n+1)^{2}}e^{(n+1)logx}]

I=[\frac{logx}{n+1}e^{logx^{(n+1)}}]-[\frac{1}{(n+1)^{2}}e^{logx^{(n+1)}}]

I=[\frac{logx}{n+1} x^{(n+1)}]-[\frac{1}{(n+1)^{2}}x^{(n+1)}]

Thus,

Integration of I= \int {x^{n}logx \, dx=[\frac{logx}{n+1} x^{(n+1)}]-[\frac{1}{(n+1)^{2}}x^{(n+1)}]

3 0
3 years ago
What is the equation of a line that is parallel to −x+3y=6 and passes through the point (3, 5) ? Enter your answer in the box.
adell [148]
Find slope: parallel lines have same slope

−x+3y=6
+x +x
----------------
3y=x+6
3/3y=x/3+6/3
y=1/3x+2

Slope=1/3

Use slope and point (3, 5) to find b, y- intercept
y=mx+b
(5)=(1/3)(3)+b
5=1+b
5-1=1-1+b
4=b

Now we put it all together using m=1/3 and b=4
y=1/3x+4
3 0
3 years ago
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