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2 years ago

In a chemical reaction, when particle size is reduced, the rate of reaction increases because of increased surface area of the

Chemistry

1 answer:

Nutka1998 [239]2 years ago

3 0

Answer:

option A

for more information, refer to brainly.com/question/13441946

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How many moles are in 5.25 L of oxygen gas as stp

Masteriza [31]

Answer:

The correct answer is 0, 235 mol

Explanation:

We use the formula PV =nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol:

1 atm x 5, 25l = n x 0, 082 l atm / K mol x 273 K

n= 1 atm x 5, 25l /0, 082 l atm / K mol x 273 K

n= 0, 235 mol

8 0

3 years ago

Hot glass looks the same as cold glass?

Finger [1]

Answer:

This is true. A hot glass does look the same as a cold glass. Glass won't change its look if it's below 648 degrees Celsius.

7 0

3 years ago

Read 2 more answers

By what mechanism does cyclohexanol react when treated in sulfuric acid and what compound results?A) E 1; methoxycyclohexane B)

tensa zangetsu [6.8K]

Answer:

E 1: cyclohexene

Explanation:

This reaction is an example of the dehydration of cyclic alcohols. The reaction proceeds in the following steps;

1) The first step of the process is the protonation of the cyclohexanol by the acid. This now yields H2O^+ attached to the cyclohexane ring.

2) the water molecule, which a good leaving group now leaves yielding a carbocation. This now leaves a cyclohexane carbocation which is highly reactive.

3) A water molecule now abstracts a proton from the carbon adjacent to the carbocation leading to the formation of cyclohexene and the regeneration of the acid catalyst. This is an E1 mechanism because it proceeds via a carbocation intermediate and not a concerted transition state, hence the answer.

8 0

4 years ago

Suppose you store a 15.5 g piece of aluminum (Cp of Al = 0.902 J/g⁰C) in the refrigerator at 2.3⁰C and then drop it into your co

Scorpion4ik [409]

Answer:

605.4 J

Explanation:

When a certain substance absorbs a certain amount of energy, its temperature increases according to the equation:

$Q=mC\Delta T$

where

Q is the heat absorbed

m is the mass of the substance

C is the specific heat capacity of the substance

$\Delta T$ is the change in temperature

In this problem, we have:

m = 15.5 g is the mass of the piece of aluminium

C = 0.902 J/g⁰C is the specific heat of the aluminium

$\Delta T = 45.6-2.3=43.3^{\circ}C$ is the change in temperature of the aluminium (in fact, at thermal equilibrium, the block of aluminium reaches the same final temperature as the coffee)

Therefore, the energy absorbed is

$Q=(15.5)(0.902)(43.3)=605.4 J$

3 0

3 years ago

Suppose a mercury thermometer contains 3.250g of mercury and has a capillary that is 0.180mm in diameter.. How far does the merc

Helga [31]

1) You need to get volume of both temperatures by using first attached formula V= Mass/Density $V_1 = (3.250 g)/(13.596 g/(cm^3)) = .2390 cm^3
At 25 degrees C (V_2e have:

V_2 = (3.250 g)/(13.534 g/(cm^3)) = .2401 cm^3$

2) Using the second formula you get the height of 0 degree
$h = V/(pi * r^2)


h_1 =(.2390 cm^3)/(pi*(.009 cm)^2) = 939.2 cm$

(radius in cm is $(0.180 mm) / 2 * (1 cm)/(10 mm) or .009 cm$

3) Then with h1 you can easily get the height of 25 degrees
$h_2 =(.2401 cm^3)/(pi*(.009 cm)^2) = 943.5 cm$

Subtract 943.5 cm - 939.2 cm, and obtain a rise in mercury height of 4.3 cm

5 0

3 years ago

Read 2 more answers