If the heat of fusion of water is 3.4 × 10^2 joule/gram, the heat energy amount required to change 15.0 grams of ice at 0°c to 15.0 grams of water at 0°c is 5100 joule (5100 = 3.4 x 10^2 x 15).
The problem above can be solved by using the heat of fusion formula. The formula for calculating the heat of fusion described as C = q/m, where: C is the heat of fusion, q is the amount of heat energy required, and m is the mass of the object.
The balanced equation:
2 H₂ + O₂ → 2 H₂O
moles of Hydrogen = mass of hydrogen ÷ molar mass of hydrogen
= 45.7 g ÷ 2 g/mol
= 22.85 mol
Now, the mole ratio of O₂ : H₂ is 1 : 2
which means that there are two times as much moles of H₂ as O₂ taking
part in the reaction
Thus since moles of H₂ = 22.85 mol
then moles of O₂ = 22.85 ÷ 2 = 11.425 mol
Mass of O₂ = moles of O₂ × molar mass of O₂
= 11.425 mol × 32 g/mol
= 365.6 g
∴ <span>grams of oxygen are needed to react with 45.7 grams of hydrogen is 365.6g</span>
Answer:
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Explanation:
Answer:
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