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AlexFokin [52]
3 years ago
13

How many moles are in 5.25 L of oxygen gas as stp

Chemistry
1 answer:
Masteriza [31]3 years ago
8 0

Answer:

The correct answer is 0, 235 mol

Explanation:

We use the formula PV =nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol:

1 atm x 5, 25l = n  x 0, 082 l atm / K mol x 273 K

n= 1 atm x 5, 25l /0, 082 l atm / K mol x 273 K

n= 0, 235 mol

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What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)
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Answer:

34.28 L ( 1.5*22.4 L)

Explanation:

Calculation of the moles of aluminum as:-

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At STP,  

Pressure = 1 atm  

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Using ideal gas equation as:

PV=nRT

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T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 1.5288 mol × 0.0821 L.atm/K.mol × 273.15 K

⇒V = 34.28 L ( 1.5*22.4 L)

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