Which group on the periodic table already stable?

¿Cómo afectaría la velocidad de una reacción si se enfría lentamente la mezcla de los reactivos? AYUDA

hodyreva [135]

Answer:

La velocidad de reacción se ralentizará más rápidamente de lo habitual.

Explanation:

Dado que los factores que influyen en la velocidad de una reacción química son;

1) Temperatura de la mezcla reaccionante

2) Concentración (para líquidos) y área superficial de presión (para gases) (para sólidos) de los reactivos

3) catalizador

4) Reactantes naturaleza

5) Orientación de las moléculas reactivas reactivas

Tenemos que, específicamente, disminuir la temperatura del reactivo disminuye la probabilidad de que las moléculas de los reactivos involucrados en colisiones dentro de la mezcla tengan suficiente energía (que es igual o mayor que la energía de activación, Ea) para que la reacción se complete . Es decir, habrá una disminución en las colisiones efectivas (colisiones que provocan una reacción) y la reacción se ralentizará.

Dado que la velocidad de reacción se ralentiza con el tiempo, los reactivos de enfriamiento lento ralentizan rápidamente la reacción.

8 0

4 years ago

g If 0.600 g of a gas occupies 211 mL at 24 oC and 660 mmHg of pressure, what is the molar mass of the gas

Alisiya [41]

Answer:

79.89 g/mol

Explanation:

The following data were obtained from the question:

Mass (m) of gas = 0.6 g

Volume (V) = 211 mL

Temperature (T) = 24 °C

Pressure (P) = 660 mmHg

Molar mass of gas =.?

Next, we convert 24 °C to Kelvin temperature. This can be obtained as follow:

Temperature (K) = temperature (°C) + 273

Temperature (°C ) = 24 °C

Temperature (K) = 24 + 273 = 297 K

Next, we shall convert 211 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

211 mL = 211 mL × 1 L / 1000 mL

211 mL = 0.211 L

Next, we shall convert 660 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

660 mmHg = 660 mmHg × 1 atm / 760 mmHg

660 mmHg = 0.868 atm

Next, we shall determine the number of mole of the gas. This can be obtained as shown below:

Volume (V) = 0.211 L

Temperature (T) = 297 K

Pressure (P) = 0.868 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

PV = nRT

0.868 × 0.211 = n × 0.0821 × 297

Divide both side by 0.0821 × 297

n = (0.868 × 0.211) / (0.0821 × 297)

n = 7.51×10¯³ mole.

Finally, we shall determine the molar mass of the gas as shown below:

Mass of gas = 0.6 g

Number of mole of gas = 7.51×10¯³ mole.

Molar mass of gas =.?

Mole = mass /Molar mass

7.51×10¯³ = 0.6 / Molar mass

Cross multiply

7.51×10¯³ × molar mass = 0.6

Divide both side by 7.51×10¯³

Molar mass = 0.6 / 7.51×10¯³

Molar mass of gas = 79.89 g/mol

3 0

3 years ago

A gas diffuses 1/6 times faster than hydrogen gas (H2). What is the molar mass of the gas? 59.95 g/mol 66.54 g/mol 68.68 g/mol 7

taurus [48]

Solution us here,

let the rate of diffusion of H2(r1) be x and⁷ the rate of diffusion of gas(r2) be x+x/6=7x/6.

Molar mass of H2 (M1)=2 g

Molar mass of gas(M2)= ?

Now, from the Ghram's law of diffusion of gas,

$\frac{r1}{r2} = \sqrt{ \frac{m2}{m1} } \\ or \: \frac{x}{ \frac{7x}{6} } = \sqrt{ \frac{m2}{2} } \\ or \: \frac{6}{7} = \sqrt{ \frac{m2}{2} } \\ squaring \: in \: both \: sides \\ \frac{36}{49} = \frac{m2}{2} \\ or m2 = 1 .469$

here, it looks like I have done wrong.

But all of the answers in option are wrong.

Because, rate of diffusion of any gas is inversely proportional to the square root of its malor mass.

And in the question, gas has higher rate of diffusion than hrdrogen. So it should have molar mass less than hydrogen.

8 0

4 years ago

Read 2 more answers

suppose you mix 100.0 g of water at 22.6 oc with 75.0 g of water at 75.4 oc. what will be the final temperature of the mixed wat

Arada [10]

The temperature of mixed water is 45.230C under the conditions stated.

<h3>How can the change in temperature when mixing water be calculated?</h3>

T(final) = (m1 T1 + m2 T2) / (m1 + m2), at which m1 and m2 are indeed the weight training of the water in the initial and 2nd canisters, T1 is the water temperature in the first container, and T2 is the water temperature in the second container, can be used to determine the final the water's temperature mixture.

<h3>Briefing:</h3>

The given parameters;

mass of the cold water, m = 100 g

initial temperature of the water, t₁ = 22.6 ⁰C

initial temperature of the hot water, t₂ = 75.4⁰ C

75 g is the hot water's mass.

specific heat capacity of water is 4.184 J/g⁰C

The mixture's final temperature is estimated as follows;

Based on the principle of conservation of energy;

Heat received by the ice water equals heat lost by the hot water.

mcΔθ₂ = mcΔθ₁

75 x 4.184 x (75.4 - T) = 100 x 4.184 x (T - 22.6)

75 x (75.4 - T) = 100 x (T - 22.6)

(75.4 - T) = 1.333(T - 22.6)

75.4 - T = 1.333T - 30.1258

75.4 + 30.1258 = 1.333T + T

105.5258 = 2.333T

T = 45.2318⁰C

To know more about temperature visit :

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5 0

2 years ago

the difference between these two measurements: 60 m and 60.00 m How many sig figs does each contain? Clearly explain which digit

tensa zangetsu [6.8K]

This problem is providing two measurements, 60 m and 60.00 m and asks for the difference in the significant digits, accuracy, uncertainty, whether they are the same or not and how they differ.

<h3>Significant figures:</h3>

In chemistry, the use of significant figures is crucial, because they define the most appropriate way to report a measurement. Thus, we can say that the more decimals a measurement has, the more accurate and the less uncertain it is. Also, if no decimal places are present, tracking zeros are not significant.

In such a way, one can conclude that 60 m has just one significant figure (0 does not count) whereas 60.00 m has four (there is a decimal making all zeros significant), 60.00 m is more accurate as more decimal places are reported. On the other hand 60 m is the more uncertain as less decimals contribute to its accuracy.

In addition, we say they can be the same measurement, as long as they represent the same idea, sixty meters, the thing is 60.00 m is more accurate yet they refer to the same measurement.

Learn more about significant figures: brainly.com/question/11904364

4 0

3 years ago