Answer:
Assuming this is the full problem.
3x^2-8x+4
Step-by-step explanation:
Answer:
51.63m^3
Step-by-step explanation:
The figure is made up of a rectangle, triangle and a semi circle
Area of the figure = Area of triangle + rectangle + semicircle
Area of the triangle = 1/2 * base * height
Area of the triangle = 1/2 * 3 * 5
Area of the triangle = 15/2
Area of the triangle = 7.5m^3
Area of the rectangle = Length * Width
Area of the rectangle = 6 * 5
Area of the rectangle = 30m^2
Area of the semicircle = πr²/2
Area of the semicircle = π(3)²/2
Area of the semicircle = 3.14(9)/2
Area of the semicircle = 3.14 * 4.5
Area of the semicircle = 14.13m^2
The area = 30 + 14.13+7.5
Area of the figure = 51.63m^3
Since 6 is positive, it's (x+blank)^2
6/2=3, and (x+3)^2 = x^2+6x+9. We have x^2+6x-2, so we have to add 9 to both sides to get (x+3)^2-2=9, then subtract 9 from both sides to get
(x+3)^2-11=0, or (x+3)^2=11. Square root both sides to get x+3=sqrt(11), and x=sqrt(11)-3, which is approximately 0.32
Answer: 4 units to the right, 3 units up
Hope this helped! :)
Answer:
60.25≈60.3°
Step-by-step explanation:
tanФ=14/8=1.75
Ф=arctan=1.75
tan-1
60.25≈60.3
