Answer:
<em>6</em><em>4</em><em> </em><em>IS</em><em> </em><em>THE</em><em> </em><em>ANSWER</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
Step-by-step explanation:
<em>Given that X - the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.</em>
<em />
<em>Height of male pilot = 74.2 inches</em>
<em />
<em>We have to find the percentile</em>
<em />
<em>X = 74.2</em>
<em />
<em>Corresponding Z score = 74.2-72.6 = 1.6</em>
<em />
<em>P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%</em>
<em />
<em>i.e. only 5% are below him in height.</em>
<em />
<em>Thus the malepilot is in 5th percentile.</em>
<u>Answers </u><u>with </u><u>Method</u><u>:-</u>
1) Multiply the length value by 100,000.


2) For this, divide the length value by 1000.


3) For finding the approximate value, just multiply the value of length by 1.609.


4) Multiply the given mass value by 100.


5) Multiply the given value by 10,000.


Convert to vertex form:-
y = 5(x^2 - 2x) + 1
y = 5[(x - 1)^2 - 1] + 1
y = 5(x - 1)^2 - 4
vertex is (1, -4)