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2 years ago

Help- i dont understand Just 10 11 and 12 please!

Mathematics

1 answer:

katrin [286]2 years ago

6 0

10. acute angles: 0
Right angles: 4
Obtuse angles: 0
Perpendicular lines: 0
Parallel lines: 2

11. Acute angles: 2
Right angles: 0
Obtuse angles: 1
Perpendicular lines: 0
Parallel lines: 0

12. H

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The graph below shows the relationship between the amount of peanuts and the amount of chocolate in different packages of snack

Tomtit [17]

Answer:

Option (B)

Step-by-step explanation:

Since the linear graph is passing through the origin, there is a proportional relationship between the amount of chocolate (C) and amount of peanuts (P) used in the package of snacks mix,

P ∝ C

P = kC

k = $\frac{P}{C}$

Here k = proportionality constant

Since, the given line passes through a point (3, 2),

k = $\frac{2}{3}$

Therefore, ratio of chocolate and peanuts mixed is $\frac{2}{3}$ .

Option (B) is the correct option.

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3 years ago

Solve for u. <br><br>u +5.96 = 9.39

Bad White [126]

Answer:

u equals 3.43 because you subtract from both sides.

3 0

2 years ago

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Mrs. Rodriguez wants to pay her restaurant bill which is $24.00. If Mrs. Rodriguez wants to leave a 20% tip on the total, how mu

Stella [2.4K]

Answer:

28.80

Step-by-step explanation:

I took the test on edge 2020

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2 years ago

Read 2 more answers

I have like 20 minutes please help<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D-7x%2B10%3D0" id="TexFormula1" title="x^{2}-7x+10

Mandarinka [93]

Answer: Hmm Ok i do this-

Step-by-step explanation:

Wait are we trying to find x?

Ok so for the first one x = 5 and for the second one x = 2

3 0

3 years ago

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

7 0

3 years ago