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2 years ago

Identify the segments that are parallel, if any, if

Mathematics

1 answer:

Vika [28.1K]2 years ago

8 0

Answer:

The answer is C

Step-by-step explanation:

it is C because parallel lines don't intercept the go up or across but they don't touch, just imagine it isn't graphed.

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A teacher buys packs of notebooks to give to his students. The ratio of gold notebooks to red notebooks is represented in the ta

Ber [7]

Answer:

40 gold notebooks

Step-by-step explanation:

5:3 gold notebooks to red notebooks so using this we can set up a proportion

5 x

-- = ---

3 24

cross multiplying

3x = 120

x= 40

so there are 40 gold notebooks if there are 24 red notebooks

3 0

3 years ago

Read 2 more answers

4. triangle FBT is similar to triangle ADQ with a scale factor of 5/3. Complete the table below.

Bogdan [553]

Triangle FBT is similar to triangle ADQ with a scale factor of 5/3. AD = 9; BF = 15, DQ = 6; BT = 10, FT = 21; AQ = 12.6

∠F = ∠A = 40°, ∠Q = ∠T = 55°, ∠B = ∠D = 85°

<h3>What are similar triangles?</h3>

Similar triangles are triangles that have the same shape and the ratio of their corresponding sides are in the same proportion. Corresponding angles are equal.

triangle FBT is similar to triangle ADQ with a scale factor of 5/3.

AD = 9; BF = 9 * 5/3 = 15

DQ = 6; BT = 6 * 5/3 = 10

FT = 21; AQ = 21 * 3/5 = 12.6

∠F = ∠A = 40°, ∠Q = ∠T = 55°, ∠B = ∠D = 85°

Find out more on similar triangles at: brainly.com/question/2644832

4 0

2 years ago

Help Plss <br>How many solutions do y=5-2x and 4x+2y = 10 have?

tia_tia [17]

y=2x+5

2(2x+5)+4x=10

4x+10+4x=10

8x=20

So there's one solution, x=2.5

5 0

3 years ago

What is the smallest value of n such that an algorithm whose running time is 100n 2 runs faster than an algorithm whose running

Semmy [17]

Answer:

n = 15

Step-by-step explanation:

For inputs of the value of n, the running time for the algorithm A is 100n^2 and that of B is 2^n.

If A is to run faster than B, 100n^2 must be smaller than 2^n.

Let's check from n = 1 to know the value of n that fits

n = 1

100(1)^2 > 2^1

100 > 2

n = 2

100(2)^2 > 2^2

400 > 4

n = 4

100(4)^2 > 2^4

1600 > 16

n = 8

100(8)^2 > 2^8

6400 > 2^8

n = 16

100(16)^2 < 2^16

25600 < 2^16

This implies that between n = 8 and 16, A starts to run faster than B

n = (8+16)/2 = 12

100(12)^2 > 2^12

14400 > 2^12

n = (12+16)/2 = 14

100(14)^2 > 2^14

19600 > 2^14

n = (14+16)/2

n = 15

100(15)^2 < 2^15

22500 < 2^15

At n= 15, A starts running faster than B

8 0

3 years ago

The group is planning to build a fence around the garden. How many yards of fencing materials do they need for the fence? Show y

garri49 [273]

Answer:

They need 130 yds to build up the fence.

Step-by-step explanation:

Attached you can find a picture that will guide the explanation. We will assume that each line is supposed to be a fence. We will assume also that the diagonals that cross any subfield that has the same vegetable is unnecessary. That is that the diagonal of the tomatoes and the watermelon are not going to be built.

Recall that the red peppers area is a right triangle. So, using pythagora's theorem, we have that

$b^2 +12^2 = 15^2$ so $b=15^2-12^2$

which gives us that b = 9.

On the same fashion, the diagonal of the spinach-celery sector is $\sqrt[]{8^2+6^2}=10$ . Recall that the field is a rectangle, so the perimeter of the outter fence is 2*(12+6)+2*(8+9) = 70 yds. Then, the total perimeter is given by

outter fence (70)+

fence spinach-watermelon (8) +

fence red peppers-watermelon(12)+

fence red peppers-carrots (15)+

fence carrots-tomatoes (9)+

fence celery-tomatoes(6) +

fence spinach-celery(10)

= 130 yds

(if the diagonals of tomatoes and watermelon are added, the same procedure applies. watermelon diagonal is 14.42 yds and tomatoes diagonal is 10.81 yds)

6 0

4 years ago