3 years ago

10 oz for $2.68 What is the price for 1 oz? |

Mathematics

1 answer:

Mazyrski [523]3 years ago

6 0

Around $0.26. That’s your answer.

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An electronic system has each of two different types of components in joint operation. Let X and Y denote the lengths of life, i

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Answer:

The average cost is $E(C) = 66$

The standard deviation of cost is $\sigma = 9.798$

Step-by-step explanation:

From the question we are told that

$E(X) = 4$

$E(Y) = 2$

$E(X^2) = 24$

$E(Y^2) = 8$

The cost of replacing the two component is C = 50 + 2 X + 4 Y

The variance of X is mathematically represented as

V(X) = $E(X^2) - [E(X)]^2$

Substituting values

$V[X] = 24 - 4^2$

$V[X] =8$

The variance of Y is mathematically represented as

V(Y) = $E(Y^2) - [E(Y)]^2$

Substituting values

$V[Y] = 8 - 2^2$

$V[X] =4$

The average of replacing the two component is

$E(C) = 2 * E(X) + 4* E(Y)$

substituting value

$E(C) = 50 + 2 * (4) + 4* (2)$

$E(C) = 66$

The variance of replacing the two component is

$V(C) = V(50 + 2X +4Y)$ Note: The variance of constant is zero

and X and Y are independent

=> $V(C) = 2^2 * V(X) + 4^2 * V(Y)$

substituting values

=> $V(C) = 4 * 8 + 16 * 4$

=> $V(C) = 32 + 64$

=> $V(C) = 96$

The standard deviation is

$\sigma = \sqrt{V(C)}$

substituting values

$\sigma = \sqrt{96}$

$\sigma = 9.798$

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3 years ago