Answer:
- Area of circle = <u>1</u><u>2</u><u>.</u><u>2</u><u>5</u><u>π</u><u> </u><u>square </u><u>inches</u>
Step-by-step explanation:
In the question we are given that <u>diameter</u><u> of</u><u> </u><u>circle</u><u> </u><u>is </u><u>of </u><u>7</u><u> </u><u>inches </u>. And we have asked to find the<u> </u><u>area </u><u>of </u><u>the </u><u>circle</u><u> </u><u>in </u><u>term </u><u>of </u><u>pi </u><u>(</u><u> </u><u>π </u><u>)</u><u> </u><u>.</u>
For finding area of circle we must have to know that what is the formula for finding area of circle. So :
<u>Where</u><u> </u><u>,</u>
- π refers to <u>3.</u><u>1</u><u>4</u><u> </u><u>or </u><u>2</u><u>2</u><u>/</u><u>7</u>
- r refers to <u>radius </u><u>of </u><u>circle </u>
<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>
As in the question we are given length of<u> </u><u>diameter</u><u> </u> . So for finding area we need to find the <u>radius</u> of circle .
We know that diameter of circle is two times its radius or ,
So for radius we are dividing both side with 2 :
We get that ,
<u>Therefore</u><u> </u><u>,</u><u> </u><u>we </u><u>can </u><u>say </u><u>that </u><u>radius </u><u>of </u><u>circle</u><u> </u><u>is </u><u>half </u><u>of </u><u>its </u><u>diameter</u><u> </u><u>.</u>
Now using this firstly we are finding radius of circle . So :
- <u>Therefore</u><u> </u><u>,</u><u> </u><u>radius </u><u>of </u><u>circle </u><u>is </u><u>7</u><u>/</u><u>2</u><u> </u><u>inches </u><u>.</u>
Now , we are moving towards our<u> </u><u>final </u><u>solution</u><u> </u><u>.</u>
<u>So </u><u>,</u>
Calculating further :
After multiplication of 7/2 with 7/2 we get :
On dividing 49 by 4 we get :
Remember one thing , we haven't put value of π as 22/7 or 3.14 because in the question it is given that we have to find the area of circle in <u>terms </u><u>of </u><u>pi </u><u>.</u>
- <u>Henceforth</u><u> </u><u>,</u><u> </u><u>in </u><u>terms </u><u>of </u><u>pi </u><u>(</u><u> </u><u>π </u><u>)</u><u> </u><u>area </u><u>of </u><u>circle</u><u> </u><u>having</u><u> </u><u>diameter</u><u> </u><u>7</u><u> </u><u>inches </u><u>is </u><em><u>1</u></em><em><u>2</u></em><em><u>.</u></em><em><u>2</u></em><em><u>5</u></em><em><u>π</u></em><em><u> </u></em><em><u>inches²</u></em><em><u> </u></em><em><u>.</u></em>
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<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>L</u><u>e</u><u>a</u><u>r</u><u>n</u><u>i</u><u>n</u><u>g</u></h2>