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2 years ago

8

Kristi has 2 ribbons that are the same length. She cuts each ribbon into 8 equal pieces. She uses 12 of the pieces to make brace

lets. What fraction of the ribbon did she use?

1 answer:

kykrilka [37]2 years ago

4 0

So she cuts them so each one has 8 since there are two there will be 16 pieces

Out of those 16 she uses 12

So the fraction would be 12/16

But wait! We need to simplify it

Half it

6/8

Half it again

3/4

There ya go!

:))))

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Write an equation in slope intercept form for the line that passes through (-1, -2) and (3, 4)

LenaWriter [7]

Answer:

The slope-intercept form of the line equation is:

$y=\:\frac{3}{2}x\:-\frac{1}{2}$

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

m is the slope

b is the y-intercept

Given the points

(-1, -2)

(3, 4)

Determining the slope between (-1, -2) and (3, 4)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-1,\:-2\right),\:\left(x_2,\:y_2\right)=\left(3,\:4\right)$

$m=\frac{4-\left(-2\right)}{3-\left(-1\right)}$

$m=\frac{3}{2}$

Thus, the slope of the line is:

m = 3/2

substituting m = 3/2 and the point (3, 4) in the slope-intercept form of the line equation

y = mx+b

$4=\frac{3}{2}\left(3\right)+b$

switch sides

$\frac{3}{2}\left(3\right)+b=4$

$\frac{9}{2}+b=4$

subtract 9/2 from both sides

$\frac{9}{2}+b-\frac{9}{2}=4-\frac{9}{2}$

$b=-\frac{1}{2}$

now substituting m = 3/2 and b = -1/2 in the slope-intercept form of the line equation

$y = mx+b$

$y=\:\frac{3}{2}x\:+\:\left(-\frac{1}{2}\right)$

$y=\:\frac{3}{2}x\:-\frac{1}{2}$

Therefore, the slope-intercept form of the line equation is:

$y=\:\frac{3}{2}x\:-\frac{1}{2}$

8 0

2 years ago

Please help and thank you!

Stolb23 [73]

The conversion is

$x = r \cos \theta$

$y = r \sin \theta$

So

$\dfrac y x = \tan \theta$

We're given the fairly unusual

$\theta = -\frac 5 2$

It's fairly unusual because usually an angle is given in degrees or radians, and typically the radians are a fraction times pi. We'll assume radians.

$\dfrac y x = \tan \theta = \tan(-5/2) \approx 0.747$

Ah, there's our .75. The approximate answer is

$y = 0.75 x$

Third choice.

The exact answer is

$y = x \tan( -\frac 5 2)$

also a line through the origin.

3 0

3 years ago

zzz [600]

The answer is B. 5/6

7 0

3 years ago

and what is distance jeremy jumps from the ramp to the fire escape is _______ feet (round to the nearest tenth of a foot)

Cloud [144]

Answer:

sin(70°) =10/x

The distance Jeremy jumps from the ramp to the fire escape is <u>10.6</u> feet

Step-by-step explanation:

From the question shown in the picture attached, the vertical height Jeremy has to jump is: 15 - 5 = 10 ft

A right triangle is formed, where the angle between the hypotenuse (called x) and one of the legs is: 160° - 90° = 70°, and the vertical height Jeremy has to jump, is the leg opposite to that angle.

From sine definition:

sin(70°) = opposite/hypotenuse

sin(70°) = 10/x

x = 10/sin(70°)

x = 10.6 ft

4 0

3 years ago

Let A be a set of numbers.

LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

a.

Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

So, $x+y$ is divisible by 5.

$xy=(5m)(5n)=25mn=5(5mn)$

So,

$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

b.

Let A = { 2n +1 | n ∈ Z}

Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

$x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)$

So,

$x+y$ ∉ A

$xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1$

So,

$xy$ ∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

c.

$Let A=\{2,5,8,11,14,...\}$

Let $x=2,y=5$ but $x+y=2+5=7$ ∉A

Also,

$xy=2(5)=10$ ∉A

Therefore, A is not closed under addition and multiplication.

d.

Let A = { 17n: n∈Z}

Let $x,y$ ∈ A such that $x=17n,y=17m$

Find x + y and xy

$x+y=17n+17m=17(n+m)$

$xy=(17m)(17n)=289mn=17(17mn)$

So,

$x+y,xy$ ∈ A

Therefore, A is closed under addition and multiplication.

e.

Let A be the set of nonzero real numbers.

Let $x,y$ ∈ A such that $x=-1,y=1$

Find x + y

$x+y=-1+1=0$

So,

$x+y$ ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0

3 years ago