


Answer: A.
Another way to solve by factoring 1/4.

![= [\dfrac{1}{4}(A + B)]^2](https://tex.z-dn.net/?f=%20%3D%20%5B%5Cdfrac%7B1%7D%7B4%7D%28A%20%2B%20B%29%5D%5E2%20)




Answer:
Infinite series equals 4/5
Step-by-step explanation:
Notice that the series can be written as a combination of two geometric series, that can be found independently:

The first one:
is a geometric sequence of first term (
) "1" and common ratio (r) "
", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: 
The second one:
is a geometric sequence of first term "1", and common ratio (r) "
". Again, since the common ratio is smaller than one, we can find its infinite sum:

now we simply combine the results making sure we do the indicated difference: Infinite total sum= 
Answer:
Points apply to the given situation:
(a)The puppy will run into the wall after 5 seconds
(b)The slope is -4 ft per second since the puppy is running at a rate of 4 ft per second.
(c)The y-intercept is 20 ft because the puppy is 20 feet away from the wall.
Step-by-step explanation:
We have given,
A puppy is running at a rate = 4 feet per second
A wall is 20 feet away from puppy. That means initially puppy is 20 feet away from the wall.
So, time taken by puppy to reach the wall =
i.e. time take by puppy to reach the wall = = 5 seconds
Now we write the points that apply to this situation:
(a)The puppy will run into the wall after 5 seconds
(b)The slope is -4 ft per second since the puppy is running at a rate of 4 ft per second. {Since the puppy is moving towards the wall that means horizontal distance is decreasing at a rate of -4 feet per second}
(c)The y-intercept is 20 ft because the puppy is 20 feet away from the wall.
Answer:
40
Step-by-step explanation:
(252-12)/6=40
Hi there!
The formula for a square is V = s^3. Using this formula, we can plug in the volume and solve for s.
WORK:
343 = s^3
s = 7
ANSWER:
The side length of a cube with volume 343 is 7 inches.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!