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3 years ago

Which is the slope of the line y=−3x+2?y=-3x+2?

1 answer:

5 0

The slope is -3.
Finding slope can be easy if you just remember that the formula is set up as y=mx+b.
The number in the 'm' place is always the slope.
Example: y=4x+1, the slope would be 4 because it's in the 'm' place.
If you have trouble remembering which place the slope is, trying thinking about skiing or sledding; you can only sled or ski down a Mountain slope. Mountain starts with M.
M=slope.
Hope this helps :)
If you have any questions, just let me know!

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Write the equation of the line that is parallel to y=4x-1 and passes through the point (4.9)

lutik1710 [3]

9514 1404 393

Answer:

y = 4x -7

Step-by-step explanation:

Rearranging the slope-intercept for equation, we can find the intercept:

y = mx +b

y -mx = b . . . . . subtract mx

We know the slope of the parallel line is the same as that of the given line (m=4), so we only need to find 'b'.

b = 9 -4(4) = -7

The desired equation is ...

y = mx +b

y = 4x -7

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3 years ago

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Serga [27]

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2 years ago

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zhannawk [14.2K]

Answer:

16.75

Step-by-step explanation:

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3 years ago

Let A = −2 2 1 −3 1 1 2 0 −1 and B = 2 −1 0 1 2 1 −1 −2 4 . Use the matrix-column representation of the product to write each co

BigorU [14]

Answer:

AB = $\left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]$

Each column of AB is written as a linear combination of columns of Matrix A in the explanation below.

Step-by-step explanation:

A = $\left[\begin{array}{ccc}-2&2&1\\-3&1&1\\2&0&-1\end{array}\right]$

B= $\left[\begin{array}{ccc}2&-1&0\\1&2&1\\-1&-2&4\end{array}\right]$

We need to write each column of AB as a linear combination of the columns of A so we will multiply each column of A with each column element of B to get the column of AB. So,

AB Column 1 = 2 * $\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]$ + 1 $\left[\begin{array}{ccc}2\\1\\0\end{array}\right]$ + (-1) $\left[\begin{array}{ccc}1\\1\\-1\end{array}\right]$ = $\left[\begin{array}{ccc}-3\\-6\\5\end{array}\right]$

AB Column 2 = (-1) $\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]$ + 2 $\left[\begin{array}{ccc}2\\1\\0\end{array}\right]$ + (-2) $\left[\begin{array}{ccc}1\\1\\-1\end{array}\right]$ = $\left[\begin{array}{ccc}4\\3\\0\end{array}\right]$

AB Column 3 = (0) $\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]$ + (1) $\left[\begin{array}{ccc}2\\1\\0\end{array}\right]$ + 4 $\left[\begin{array}{ccc}1\\1\\-1\end{array}\right]$ = $\left[\begin{array}{ccc}6\\5\\-4\end{array}\right]$

Finally, we can combine all three columns of AB to form the 3x3 matrix AB.

AB = $\left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]$

4 0

3 years ago