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Elza [17]
3 years ago
11

Which is the slope of the line y=−3x+2?y=-3x+2?

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
5 0
The slope is -3.
Finding slope can be easy if you just remember that the formula is set up as y=mx+b.
The number in the 'm' place is always the slope.
Example: y=4x+1, the slope would be 4 because it's in the 'm' place.
If you have trouble remembering which place the slope is, trying thinking about skiing or sledding; you can only sled or ski down a Mountain slope. Mountain starts with M.
M=slope.
Hope this helps :)
If you have any questions, just let me know!
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Write the equation of the line that is parallel to y=4x-1 and passes through the point (4.9)
lutik1710 [3]

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Answer:

  y = 4x -7

Step-by-step explanation:

Rearranging the slope-intercept for equation, we can find the intercept:

  y = mx +b

  y -mx = b . . . . . subtract mx

We know the slope of the parallel line is the same as that of the given line (m=4), so we only need to find 'b'.

  b = 9 -4(4) = -7

The desired equation is ...

  y = mx +b

  y = 4x -7

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Let A = −2 2 1 −3 1 1 2 0 −1 and B = 2 −1 0 1 2 1 −1 −2 4 . Use the matrix-column representation of the product to write each co
BigorU [14]

Answer:

AB = \left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]

Each column of AB is written as a linear combination of columns of Matrix A in the explanation below.

Step-by-step explanation:

A = \left[\begin{array}{ccc}-2&2&1\\-3&1&1\\2&0&-1\end{array}\right]

B= \left[\begin{array}{ccc}2&-1&0\\1&2&1\\-1&-2&4\end{array}\right]

We need to write each column of AB as a linear combination of the columns of A so we will multiply each column of A with each column element of B to get the column of AB. So,

AB Column 1 = 2 * \left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]  + 1 \left[\begin{array}{ccc}2\\1\\0\end{array}\right] + (-1) \left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}-3\\-6\\5\end{array}\right]

AB Column 2 = (-1)\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right] + 2\left[\begin{array}{ccc}2\\1\\0\end{array}\right] + (-2)\left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}4\\3\\0\end{array}\right]

AB Column 3 = (0)\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right] + (1)\left[\begin{array}{ccc}2\\1\\0\end{array}\right] + 4\left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}6\\5\\-4\end{array}\right]

Finally, we can combine all three columns of AB to form the 3x3 matrix AB.

AB = \left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]

4 0
3 years ago
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