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Ira Lisetskai [31]
3 years ago
12

Determine the center and radius of the following circle equation: x^2+y^2+20x+8y+35=0

Mathematics
1 answer:
natta225 [31]3 years ago
4 0

Answer:

center: (-10,-4)

radius: 9

Step-by-step explanation:

Let's start off by moving the 35 to the other side and grouping the x and y terms we have

(x²+20x)+(y²+8y)= -35

Next we take the term with the x coeficcent, divide it by 2, and square it

so

for the x we would do (20/2)²=100

and make sure we add that to the 35

(x²+20x+100)+(y²+8y+16)= -35+100+16

next factor everythign to get

(x+10)²+(y+4)²=81

therefore the center is (-10,-4)

and the radius is √81 or 9

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ruslelena [56]

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C

Step-by-step explanation:

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8 0
4 years ago
One number is 28 less than another number. If the sum of the two numbers is 92, find the two numbers.
kiruha [24]

Answer:

The two numbers are <em>32</em> and <em>60</em>.

Step-by-step explanation:

We can create two simultaneous equations to solve this problem using the information given in the question.

Let number 1 = x

Let number 1 = y

x = y - 28 -> ( 1 )

x + y = 92 -> ( 2 )

We can solve simultaneous equations using substitution or elimination. For this question, we will use substitution as it is the easier option.

Substitute ( 1 ) into ( 2 ):

x + y = 92 -> ( 2 )

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