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2 years ago

13

PLEASE HELP ASAP!!!! 100% CORRECT ANSWERS ONLY PLEASE!!!!

2 answers:

Setler [38]2 years ago

7 0

That would be the last choice.
The formula for the circumference = 2 pi r.

jolli1 [7]2 years ago

6 0

Your answer is
( Find the length of the diameter and the length of the circumference of the circle. Divide the length of the circumference by the length of the diameter. Set up an equation showing the ratio of the circumference to the diameter equal to π . Then rearrange the equation by solving it for the circumference. Substitute 2 times the radius for the diameter. )
give me brainlyesttt!!!!!

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△klm, lm=20 sqrt 3 m∠k=105°, m∠m=30° find: kl and km

Anarel [89]

Answer:

KL = $\frac{20\sqrt{6}}{1+\sqrt{3}}$ = 17.93

MK = $\frac{40\sqrt{3}}{1+\sqrt{3}}$ = 25.36

Explanation:

According to the Law of Sines:

$\frac{a}{sinA}=\frac{b}{sinB}= \frac{c}{sinC}$

where:

A, B, and C are angles

a, b, and c are the sides opposite to the angles

First of all, let's find m∠L: the sum of the angles of a triangle is 180°, therefore

m∠K + m∠L + m∠M = 180°

m∠L = 180° - m∠K - m∠M

m∠L = 180° - 105° - 30°

m∠L = 45°

Now, we can apply the Law of Sines to our case (see picture attached):

$\frac{LM}{sinK}=\frac{MK}{sinL}=\frac{KL}{sinM}$

Let's solve one side at the time:

$\frac{LM}{sinK}=\frac{MK}{sinL}$

$\frac{20\sqrt{3}}{sin(105)}=\frac{MK}{sin(45)}$

$MK = \frac{20\sqrt{3} }{sin(105)} \cdot sin(45)$

MK = $\frac{40\sqrt{3} }{1+\sqrt{3} }$ = 25.36

Similarily:

$\frac{LM}{sinK}=\frac{KL}{sinM}$

$\frac{20\sqrt{3}}{sin(105)}=\frac{KL}{sin(30)}$

$KL = \frac{20\sqrt{3} }{sin(105)} \cdot sin(30)$

KL = $\frac{20\sqrt{6}}{1+\sqrt{3}}$ = 17.93

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