Answer:
Step-by-step explanation:
We can use formula (a-b)² = a² -2ab + b².
In our example a = 3c^4 and b = 5c^6
![(3c^{4} - 5c^{6})^{2} = [3c^{4} ]^{2} - 2*3c^{4} *5c^{6} + [5c^{6}]^{2}=\\=9c^{8} -30c^{10} + 25c^{12}](https://tex.z-dn.net/?f=%283c%5E%7B4%7D%20-%205c%5E%7B6%7D%29%5E%7B2%7D%20%3D%20%5B3c%5E%7B4%7D%20%5D%5E%7B2%7D%20-%202%2A3c%5E%7B4%7D%20%2A5c%5E%7B6%7D%20%2B%20%5B5c%5E%7B6%7D%5D%5E%7B2%7D%3D%5C%5C%3D9c%5E%7B8%7D%20-30c%5E%7B10%7D%20%2B%2025c%5E%7B12%7D)
Alright, the zeroes are where it intersects with the X-axis so...
4) -15 and 10
5) 6 and 18
6) -5 and 0
7) -20 and -8
8) 2 and 10
9) -21 and 14
Hope I was able to help you :)
I am going to give a few answers:
497,543
504,690
501,991
496,900
For the first one EF is 119 degrees now since that's made with two radii it makes a central angle so whatever that arc is the central angle will be the same. fro the second one since SRQ is 52 degrees you just take that and subtract it from 180 to get SQ. I'm not quite sure about the third one. the forth you are taking the measurement of the arc its connected to and dividing that by 2 so it would be 71 degrees. I'm pretty sure in right.
