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3 years ago

20 POINTS FOR YOUR TIME! PLEASE HELP!!

1 answer:

3 0

For a relation to be function, every x value should have its unique image in co-domain. If x is related to more than one y value, then that relation is not a function
In 1, as you can see, 1 related to -7 as well as 8. Which means 1 has two images viz. -7 and 8. But for a relation to be function, x should have only one image. Thus, it is not a function.
The worst is the 4th one in which -2 has 4 images.
Therefore, only relation B is a function.

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F(x) = 5x2 – 20x + 26<br> In vertex form

mihalych1998 [28]

Answer:

$f(x)=5(x-2)^{2}+6$

Step-by-step explanation:

we have

$f(x)=5x^{2} -20x+26$

This is the equation of a vertical parabola open upward

The vertex is a minimum

The equation of a vertical parabola in vertex form is equal to

$f(x)=a(x-h)^2+k$

where

(h,k) is the vertex

Convert the given function to vertex form

Factor the leading coefficient

$f(x)=5(x^{2} -4x)+26$

Complete the square

$f(x)=5(x^{2} -4x+4)+26-20$

$f(x)=5(x^{2} -4x+4)+6$

Rewrite as perfect squares

$f(x)=5(x-2)^{2}+6$ ------> equation in vertex form

The vertex is the point (2,6)

6 0

3 years ago

If my parents give a waiter a 15% tip if the total amount of lunch was 42.00 what should be paid to the waiter as a tip

hodyreva [135]

Tip = 15/100 x 42 = $6.3

7 0

3 years ago

Read 2 more answers

Use a graphing utility to approximate (to two decimal places) any relative

iogann1982 [59]

Answer:

Relative minima at $(-\frac{7}{2} , -\frac{49}{4} )$ , and relative maxima DNE.

Step-by-step explanation:

The given function is f(x) = x (x + 7) ...... (1)

We have to calculate the relative maxima and relative minima at point (x, y).

Rearranging the function given above we get.

$y= x^{2} +7x = (x + \frac{7}{2} )^{2} -\frac{49}{4}$

⇒ $y+ \frac{49}{4} = (x + \frac{7}{2} )^{2}$

Now, this is an equation of parabola having vertex at $(-\frac{7}{2} , -\frac{49}{4} )$ and the axis is parallel to positive Y-axis.

Therefore, the function(1) has a relative minima at $(-\frac{7}{2} , -\frac{49}{4} )$ , and the relative maxima DNE. (Answer)

3 0

3 years ago

regular octagon rotates 360° about its center. How many times does the image of the octagon coincide with the preimage during th

Galina-37 [17]

An octagon has 8 sides, a rotation of 45° (360°/8) will map the octagon onto its preimage. Answer is 8.

7 0

3 years ago

A picture is x+20 cm in width and 2x-10 cm in length. The frame is a

Jobisdone [24]

Answer:

A = 1100cm^2

Step by step Explanation:

given the dimensions of width and length of the picture are x+20 by 2x-10 and the frame is a constant 5 cm wider from the edge of the picture to the frame, than the area of the frame is defined as (x+30)(2x)-(x+20)(2x-10) = 30x+200.

If the width is equal to the length which I assume is true if the width is constant.

than x+30=2x, which means x = 30.

if this is true than 30(30)+200 = 1100cm^2

8 0

3 years ago