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Svetlanka [38]
1 year ago
15

A sweater is marked 30% off the original price. The original price was $37.50. What is the sale price of the sweater before sale

s tax?
(I will give brainliest if you show your work)!!
Mathematics
2 answers:
Brums [2.3K]1 year ago
5 0

Answer:

  $26.25

Step-by-step explanation:

To find the discounted price, subtract the discount amount from the original price. The amount of the discount is the product of the discount rate and the original price.

__

  discounted price = original price - (original price) × (discount rate)

You can calculate it this way, or you can factor out the original price:

  discounted price = (origina price) × (1 - discount rate)

  = $37.50 × (1 -0.30) = $37.50 × 0.70 = $26.25

The sale price of the sweater is $26.25.

__

<em>Additional comment</em>

The amount of the discount is ...

  $37.50 × 0.30 = $11.25

which makes the discounted price be ...

  $37.50 -11.25 = $26.25

NeTakaya1 year ago
5 0
Answer: 26.25

Work:
Our output value is 37.50.

We represent the unknown value with x

From step 1 above, $37.50=100%​.

So, x=30%​.

This results in a pair of simple equations:

$37.50=100%( 1). $x=30%(2)​.

By dividing equation 1 by equation 2 and noting that right hand side of both
equations have the same unit (%); we have

37.5 = 100%
—— ———
X. 30%

Again, the reciprocal of both sides gives

X. 30%
——. ————
37.5 = 100%

30% of 37.5 is 11.25


37.5- 11.25 is 26.25






Hopefully this makes sense
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Chris has $170.00. Candies cost $8.50 each. How many candies can Chris buy? $<br> Blank
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3 years ago
Birth weights at a local hospital have a Normal distribution with a mean of 110 oz and a standard deviation of 15 oz. The propor
OLga [1]

Answer:

The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 110, \sigma = 0.15

The proportion of infants with birth weights between 125 oz and 140 oz is

This is the pvalue of Z when X = 140 subtracted by the pvalue of Z when X = 125. So

X = 140

Z = \frac{X - \mu}{\sigma}

Z = \frac{140 - 110}{15}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 125

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 110}{15}

Z = 1

Z = 1 has a pvalue of 0.8413

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4 0
3 years ago
I will give lots of points please help
aalyn [17]

Answer:

a)  81π  in³

b)  27  in³

c)  divide the volume of the slice of cake by the volume of the whole cake

d)  10.6%

e)  see explanation

Step-by-step explanation:

<h3><u>Part (a)</u></h3>

The cake can be modeled as a <u>cylinder </u>with:

  • diameter = 9 in
  • height = 4 in

\sf Radius=\dfrac{1}{2}diameter \implies r=4.5\:in

\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

\begin{aligned}\sf \implies \textsf{Volume of the cake} & =\pi (4.5)^2(4)\\ & = \sf \pi (20.25)(4)\\ & = \sf81 \pi \:\: in^3\end{aligned}

<h3><u>Part (b)</u></h3>

\begin{aligned}\textsf{Circumference of the cake} & = \sf \pi d\\& = \sf 9 \pi \:\:in\end{aligned}

If each slice of cake has an arc length of 3 in, then the volume of each slice is 3/9π of the entire volume of the cake.

\begin{aligned}\implies \textsf{Volume of slice of cake} & = \sf \dfrac{3}{9 \pi} \times \textsf{volume of cake}\\\\& = \sf \dfrac{3}{9 \pi} \times 81 \pi\\\\& = \sf \dfrac{243 \pi}{9 \pi}\\\\& = \sf 27\:\:in^3\end{aligned}

<h3><u>Part (c)</u></h3>

The volume of each slice of cake is 27 in³.

The volume of the whole cake is 81π in³.

To calculate the probability that the first slice of cake will have the marble, divide the volume of a slice by the volume of the whole cake:

\begin{aligned}\implies \sf Probability & = \sf \dfrac{27}{81 \pi}\\\\& = \sf 0.1061032954...\\\\ & = \sf 10.6\% \:\:(1\:d.p.)\end{aligned}

<h3><u>Part (d)</u></h3>

Probability is approximately 10.6%  (see above for calculation)

<h3><u>Part (e)</u></h3>

If the four slices of cake are cut and passed out <em>before </em>anyone eats or looks for the marble, the probability of getting the marble is the same for everyone. If one slice of cake is cut and checked for the marble before the next slice is cut, the probability will increase as the volume of the entire cake decreases, <u>until the marble is found</u>.  So it depends upon how the cake is cut and distributed as to whether Hattie's strategy makes sense.

3 0
2 years ago
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TEA [102]

Answer:

y= -2x -8

Step-by-step explanation:

I will be writing the equation of the perpendicular bisector in the slope-intercept form which is y=mx +c, where m is the gradient and c is the y-intercept.

A perpendicular bisector is a line that cuts through the other line perpendicularly (at 90°) and into 2 equal parts (and thus passes through the midpoint of the line).

Let's find the gradient of the given line.

\boxed{gradient =  \frac{y1 -y 2}{x1 - x2} }

Gradient of given line

=  \frac{1 - ( - 5)}{3 - ( - 9)}

=  \frac{1 + 5}{3 + 9}

=  \frac{6}{12}

=   \frac{1}{2}

The product of the gradients of 2 perpendicular lines is -1.

(½)(gradient of perpendicular bisector)= -1

Gradient of perpendicular bisector

= -1 ÷(½)

= -1(2)

= -2

Substitute m= -2 into the equation:

y= -2x +c

To find the value of c, we need to substitute a pair of coordinates that the line passes through into the equation. Since the perpendicular bisector passes through the midpoint of the given line, let's find the coordinates of the midpoint.

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= ( \frac{3  -  9}{2} , \frac{1 - 5}{2} )

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= ( - 3 , - 2)

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c= -8

Thus, the equation of the perpendicular bisector is y= -2x -8.

5 0
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