A rectangular carpet is 2 times as long as it is wide. Its width is 5
2 answers:
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We know these variables:
W1B = Weight of the truck 1 before starting the filling.
W1A = Weight of the truck 1 when filled.
R1F = Rate of change (Truck 1 being filled)
W2B = Weight of the truck 2 before starting the filling.
W2A = Weight of the truck 2 when filled.
R2F = Rate of change (Truck 2 being filled)
Given that a conveyor belt pours sand into the truck and stops when filled, then the amount of sand, when the truck is filled to capacity, is<span>:
</span>
<span>
Let's analyze Truck 1:
Given that the rate of change is:
</span>
<span>
This means that in 1min the amount of sound poured is 1/4Ton, then the time </span>elapsed when filled using rule of three is:
A similar analysis happens with Truck 2:
Given that the rate of change is:
Then:
Now we can find two straight lines:
Truck 1:
∴
Truck 2:
∴
<span>The trucks are the same weight when they have the same amount of sand, so solving for t:
</span>
Finally, the amount of sand in each truck:
W1B = Weight of the truck 1 before starting the filling.
W1A = Weight of the truck 1 when filled.
R1F = Rate of change (Truck 1 being filled)
W2B = Weight of the truck 2 before starting the filling.
W2A = Weight of the truck 2 when filled.
R2F = Rate of change (Truck 2 being filled)
Given that a conveyor belt pours sand into the truck and stops when filled, then the amount of sand, when the truck is filled to capacity, is<span>:
</span>
<span>
Let's analyze Truck 1:
Given that the rate of change is:
</span>
<span>
This means that in 1min the amount of sound poured is 1/4Ton, then the time </span>elapsed when filled using rule of three is:
A similar analysis happens with Truck 2:
Given that the rate of change is:
Then:
Now we can find two straight lines:
Truck 1:
∴
Truck 2:
∴
<span>The trucks are the same weight when they have the same amount of sand, so solving for t:
</span>
Finally, the amount of sand in each truck: