1)
I:y=3x-4
II:9x-3y=14
substitute y into II:
9x-3*(3x-4)=14
9x-9x+12=14
12=14
this is obviously not equal so there is no solution, the lines are parallel
2)
I:y=4x+6
II:5x-y=6
substitute y into II:
5x-(4x+6)=6
5x-4x-6=6
x=12
substiute x into II:
5*12-y=6
-y=6-60
-y=-54
y=54
the solution is (12,54)
Answer:
-d-20
Step-by-step explanation:
Hope this helps!
Answer:
201.1 km²
Step-by-step explanation:
Surface area of the figure,
4πr²
= 4×π×4²
= 64π
= 201.1 km² (rounded to the nearest tenth)
To solve this I'm going to split the middle term.
First multiply the first and last terms:
24x^2
So find two numbers that multiply to 24x^2 and add to 11x.
This would be 3x and 8x
Rewrite the problem as
4x^2+3x+8x+6
Take the first and 3rd and 2nd and 4th terms
4x^2 and 8x
and
3x and 6
Factor by grouping
Take out a 4x for the first group to get 4x(x+2)
Take out a 3 for the 2nd group to get 3(x+2)
Rewrite as (4x+3)(x+2)
Hope this helps.
