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mel-nik [20]
1 year ago
7

60% of the voters favor Ms. Stein. If 200 voters are chosen at random, what is the expected number of voters who indicate favori

ng Ms. Stein?The expected number of voters who indicate favoring Ms. Stein is
Mathematics
1 answer:
damaskus [11]1 year ago
6 0

Given,

The parcentage of voters in favr of Ms Stein is 60%.

The total number of voters are 200.

The expected number of voters who indicate favoring Ms. Stein is,

\text{Expected value = probability}\times sample\text{ size}

Substituting the values,

\begin{gathered} \text{Expected value=}\frac{\text{60}}{100}\times200 \\ =120 \end{gathered}

Hence, the expected number of voters who indicate favoring Ms. Stein is 120

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You receive 15% of the profit from a car wash how much money do you receive from a profit of 300
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Answer: 45


Step-by-step explanation:


300 * 0.15 = 45



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3 years ago
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Algebraic models grade 12 math college please write the answers without explaining thank you.
Zinaida [17]

From the problem :

6^4\times6^{-5}

In multiplying expressions with the same bases, the exponent will be added accordingly.

For example :

a^m\times a^n=a^{m+n}

the exponent of a are m and n, and the product will be a raised to the sum of m and n.

Applying this to the problem, we have :

6^4\times6^{-5}=6^{4-5}=6^{-1}

The answer is d. 6^-1

6 0
1 year ago
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

7 0
2 years ago
3 1/8t=2 1/2 what is t?​
navik [9.2K]

Answer:

T=4

Step-by-step explanation:

it is just half of what the other side is if one side is like 1 1/2 then you just break the other side in half and that will give you T.

5 0
3 years ago
Solve. 3t &lt; –15 (1 point)<br> t &lt; –5<br> t &gt; –5<br> t &lt; –45<br> t &gt; –45
Kipish [7]
I hope this helps you



3t÷3 < -15÷3


t < -5
8 0
3 years ago
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