To solve:
(x-10)(x-10)
Answer: x^2-20x+100
Answer:
2 sqrt(5) OR 4.5
Step-by-step explanation:
You have to know Pythagorean theorem to solve this question.
a^2 + b^2 = c^2
To use this theorem you have to have a right triangle. There are two right triangles in your image. The lower (larger) one has two sides labeled, so you can use Pythagorean thm to find the third side. There's a short cut, bc some right triangles have easy-to-memorize lengths of the sides. 3-4-5 is one of these number sets. A multiple of this is 6-8-10. We could've solved:
b^2 + 8^2 = 10^2
But it would've come out the same. The unlabeled side is 6.
We can use the 6 and the 4 on the smaller right triangle and use the Pythagorean thm again to solve for x.
4^2 + x^2 = 6^2
16 + x^2 = 36 subtract 16 from both sides.
x^2 = 20
Take the square root of both sides.
sqrt (x^2) = sqrt 20
x = 2 sqrt(5) which is approximately 4.472.
2 sqrt(5) is an exact answer if that is what they are asking for. 4.472 is an approximation to the nearest thousandth. It would be 4.47 to the nearest hundredth or 4.5 to the nearest tenth.
Answer:
R
Step-by-step explanation:
if you look at it 0 is the first one then count up by tens Q would 48 because it’s before 50 so 50 is right next to Q so then R is before 60 and after 50 so R is 58/100
Answer:
None of the above
Step-by-step explanation:
None of the answer choices are even triangles, let alone right triangles. The sum of the two smaller sides isn't larger than the bigger side on any of the triangles, which means that they cannot be closed.
First you gotta distribute.
4 (1.75y - 3.5) + 1.25y
4 * 1.75 y = 7
4* (-3.5) = (-14)
7y - 14 + 1.25y
Combine like terms
8.25y - 14
