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Anestetic [448]
2 years ago
10

BRAINLIEST+ STARS!!

Mathematics
1 answer:
nasty-shy [4]2 years ago
6 0

<u>To find the density:</u>

 ⇒ must find the relationship between the density, mass, and volume

    ⇒ Density = \frac{mass}{volume}

<u>Let's examine the information given:</u>

  • weight: 1890g
  • dimensions: 8cm * 5cm* 5cm

<u>Let's first find the volume:</u>

   ⇒ the volume is the dimensions multiplied together

      Volume = 8cm * 5cm * 5cm = 200cm^3

<u>LEt's calculate the density now:</u>

  Density = \frac{1890g}{200cm^3} =9.45g/cm^3

<u>Answer:</u> The density of the copper is <u>9.45g/cm^3</u> or <u>Choice (A)</u>

<u></u>

Hope that helps!

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Answer:

x = 17

Step-by-step explanation:

3(x-12)=15

->

x-12+12=5+12

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0.3% of 12,000 = 36 Correct ans
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Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
2 years ago
Determine whether the relation represents a function.
-Dominant- [34]

Answer:

it does not because it would not pass the straight line test

Step-by-step explanation:

sorry if its wrong and btw your cute

6 0
2 years ago
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