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Hatshy [7]
3 years ago
15

Write an equation of the line that passes through (-2, 8) and (-4, -4)

Mathematics
1 answer:
Nady [450]3 years ago
6 0

Answer:

y=6x+20

Step-by-step explanation:


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Can anyone help me solve this.I need proper equation..Thanks​
artcher [175]

Answer:

y = 9\sqrt{2}

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin45° = \frac{1}{\sqrt{2} }

sin45° = \frac{opposite}{hypotenuse} = \frac{9}{y}

Multiply both sides by y

y × sin45° = 9, that is

y × \frac{1}{\sqrt{2} } = 9

Multiply both sides by \sqrt{2}

y = 9\sqrt{2}

3 0
3 years ago
Read 2 more answers
Jerry has reached 39% of his weekly exercise time goal so far this week if he has exercise for a total of 78 minutes this week.
kompoz [17]

Answer:

his weekly exercise time goal in minutes = 200 minutes

Step-by-step explanation:

Jerry has reached 39% of his weekly exercise time goal.

so far this week ,he has exercise for a total of 78 minutes this week.

39% of total = 78 minutes

100%= x

X=100*78/39

X=100*2

X= 200 minutes

his weekly exercise time goal in minutes = 200 minutes

3 0
3 years ago
On Monday, it took 5 builders 3 in a half hours to build a wall.
mrs_skeptik [129]

Answer:

£83.70

Step-by-step explanation:

→ First step is to find the amount of hours it takes for one builder

We know it takes 5 builders 3\frac{1}{2} hours so 1 builder would take 5 × 3\frac{1}{2} which is \frac{35}{2} hours so it takes one builder 17.5 hours to builder a wall

→ Now we know how long one work takes we need to find out the time for 2 builders

1 builder = 17.5 hours

2 builders = 17.5 ÷ 2 = 8.75 hours

So 2 builders take 8.75 hours

→ We know that each builder is paid £9.30 for each or part hour they work so

9.30 hourly pay rate × 9 hours work of work = £83.70

Each worker will be paid £83.70

6 0
3 years ago
Solve the equation 4(x-5)=2x-14
Ganezh [65]
4x-20=2x-14
-2x. -2x
2x-20=14
+20 +20
2x= 34
— —
2 2
X=17



Therefore x=17
5 0
3 years ago
Read 2 more answers
The lengths, in minutes, of the movies currently showing at a movie theater are shown in the data set. ​ ​ ​ ​Create a histogram
alexdok [17]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required lengths are not given.

I will use the following data set to answer the question.

Dataset: 35, 51, 39, 42, 68, 62, 32, 59

First, is to determine the range of the dataset

Range = Highest - Least

Range = 68 - 32

Range = 36

Next, we will make use of 4 classes. So, we divide range by 10 to get the number of class. 10 represents the interval

Class= Range/10

Class = 36/10

Class = 3.6

Class \approx 4

<em>So, we use 4 classes</em>

Plot the frequency distribution table as follows:

\begin{array}{ccc}{Intervals} & {Observations} & {Frequency} & {31-40} & {32,35,39} & {3} & {41-50} & {42} & {1} & {51-60} & {51,59} & {2} & {61-70} & {62,68} & {2}\ \end{array}

<em>See attachment for histogram</em>

5 0
3 years ago
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